c 的小问题想改成这种形式（java 会做 c 就.）例如：please input your name （你输入的名字

c 的小问题
想改成这种形式（java 会做 c 就.）
例如：please input your name
（你输入的名字）
please input your age
(你输入的年龄)
然后打印出：
Hello,（你输入的名字,（名字手写字母大写））
（几个Vowels 在你的名字里）
（你年龄(X)是odd/even）
#include
#include
struct student{
char array[999];
int age;
};
typedef struct student student;
void main(){
student *current;
char curr;
int i=0;
int j=0;
current =(student *) malloc (sizeof(student));
printf("please input your name\n");
while ((curr=getchar())!='\n')
current->array[i++]=curr;
current->array[i]='\0';
current->array[0]=toupper(current->array[0]);
printf("Hello,");
j=0;
for ( i=0;current->array[i]!='\0';i++){
printf("%c",current->array[i]);
if (current->array[i] == 'a' || current->array[i] =='A'
||current->array[i] == 'e'||current->array[i] == 'E'
||current->array[i] == 'i' ||current->array[i] == 'I'
||current->array[i] == 'o'||current->array[i] == 'O'
||current->array[i] == 'u'||current->array[i] == 'U')
j = j+1;
}
printf("!\n");
printf("%d vowels in your name.\n",j);
printf("pleae input your age\n");
scanf("%d",¤t->age);
if(current->age%2==0){
printf("your age (%d) is even\n",current->age);
}
else{
printf("your age (%d) is odd\n",current->age);
}
free(current);
}

what's wrong?
I don't know what you said.
Please write your problem!
想改成这种形式（java 会做 c 就.）
例如：please input your name
（你输入的名字）
please input your age
(你输入的年龄)
然后打印出：
Hello,（你输入的名字,（名字手写字母大写））
（几个Vowels 在你的名字里）
（你年龄(X)是odd/even）
#include
#include
struct student{
char array[999];
int age;
};
typedef struct student student;
void main(){
student *current;
char curr;
int i=0;
int j=0;
current =(student *) malloc (sizeof(student));
printf("please input your name\n");
while ((curr=getchar())!='\n')
current->array[i++]=curr;
current->array[i]='\0';
current->array[0]=toupper(current->array[0]);
printf("Hello,");
j=0;
for ( i=0;current->array[i]!='\0';i++){
printf("%c",current->array[i]);
if (current->array[i] == 'a' || current->array[i] =='A'
||current->array[i] == 'e'||current->array[i] == 'E'
||current->array[i] == 'i' ||current->array[i] == 'I'
||current->array[i] == 'o'||current->array[i] == 'O'
||current->array[i] == 'u'||current->array[i] == 'U')
j = j+1;
}
printf("!\n");
printf("%d vowels in your name.\n",j);
printf("pleae input your age\n");
scanf("%d",¤t->age);
if(current->age%2==0){
printf("your age (%d) is even\n",current->age);
}
else{
printf("your age (%d) is odd\n",current->age);
}
free(current);
}
what?
that's right?
再问： 这个代码形式是 please input your name （你输入的名字） 打印出： Hello，（你输入的名字，（名字手写字母大写）） （几个Vowels 在你的名字里） please input your age (你输入的年龄) 打印出：（你年龄(X)是odd/even） 但我想要上边的输出形式