灵鹊做题网给这方程所确定的隐函数的二阶导数,
来源：学生作业帮 编辑：灵鹊做题网作业帮 分类：数学作业 时间：2024/05/09 17:23:54
给这方程所确定的隐函数的二阶导数,
两边对x求导：y'=(1+y')cos(x+y)
得：y'=cos(x+y)/[1-cos(x+y)]
再对y'求导：y"=[-(1+y')sin(x+y)(1-cos(x+y))-cos(x+y)*(1+y')(sin(x+y)]/[1-cos(x+y)]^2
=-sin(x+y)(1+y')/[1-cos(x+y)]^2
再代入y',得：
y"=-sin(x+y)[1+cos(x+y)/(1-cos(x+y))]/[1-cos(x+y)]^2
=-sin(x+y)/[1-cos(x+y)]^3
再问： л��
得：y'=cos(x+y)/[1-cos(x+y)]
再对y'求导：y"=[-(1+y')sin(x+y)(1-cos(x+y))-cos(x+y)*(1+y')(sin(x+y)]/[1-cos(x+y)]^2
=-sin(x+y)(1+y')/[1-cos(x+y)]^2
再代入y',得：
y"=-sin(x+y)[1+cos(x+y)/(1-cos(x+y))]/[1-cos(x+y)]^2
=-sin(x+y)/[1-cos(x+y)]^3
再问： л��