x平方加x四次方等于
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(x的平方加x加1)分之x等于a∴(x²+x+1)/x=1/ax+1+1/x=1/ax+1/x=1/a-1=(1-a)/a两边平方得x²+2+1/x²=(1-a)
∵x²-3x+1=0∴x²+1=3x(x²+1)×1/x=3x×1/x∴x+(1/x)=3∴[x+(1/x)]²=3²x²+2×x×1/x+
x^2-3x+1=0x-3+1/x=0x+1/x=3(x+1/x)^2=9x^2+2+1/x^2=9x^2+1/x^2=7(x^2+1/x^2)^2=49x^4+2+1/x^4=49x^4+1/x^4
x^2-13x+1=0.x≠0.x-13+1/x=0,x+1/x=13.(x+1/x)^2=169x^2+1/x^2=169-2=167(x^2+1/x^2)^2=167^2.x^4+1/^4=167
X²+2X-1=0两边同时除以x得x+2-1/x=0x-1/x=-2两边同时平方得x²+1/x²=6两边同时平方得x4+1/x4=34
x+1/x=√5(x+1/x)²=(√5)²x²+2+1/x²=5x²+1/x²=3x²/(x^4+x²+1)分子分母除
∵x^2-3x+1=0显然x不等于0∴x-3+1/x=0∴x+1/x=3∴x^2+1/x^2+2=9∴x^2+1/x^2=7∴原式=1/(x^2+1+1/x^2)=1/(7+1)=1/8
你确定你没抄错题吗?
x²+3x+1=0除以x得x+3+1/x=0x+1/x=-3∴(x+1/x)²=x²+2+1/x²=9即x²+1/x²=9-2=7∴﹙x
x+1/x=3平方得x²+2+1/x²=9x²+1/x²=9-2=7所以x²/(x^4+x²+1)=1/(x²+1+1/x
x^2-5x+1=0显然x不是0,两边除以x有x-5+1/x=0也就是x+1/x=5所以x^2+1/(x^2)=(x+1/x)^2-2=23x^4+1/(x^4)=(x^2+1/(x^2))^2-2=
由于X^2--4X+1=0所以X=2--根号3或X=2+根号3所以X的四次方加X的负四次方的值为1/或1/
由x^2+3x+1=0得x+3+1/x=0x+1/x=-3(x+1/x)^2=x^2+1/x^2+2=9x^2+1/x^2=7原式=x^2/(x^4+3x^2+1)=1/(x^2+3+1/x^2)=1
x的平方加x的负二次方的值为7,x的四次方加x的负四次方的值为47再问:有过程吗
解x^4-7x²+6=0令t=x²≥0则t²-7t+6=0(t-6)(t-1)=0∴t=6,t=1∴x²=6,或x²=1∴x=√6,或x=-√6,或x
再问:x²(x+2)=1能求出吗?再答:-1再问:我查了,4个解
x²-4x+1=0两边同时除以xx-4+1/x=0x+1/x=4两边同时平方x²+2+1/x²=16x²+1/x²=14两边同时平方x^4+2+1/x
x^2/(x^4+1)=33x^4+3=x^2两边平方9x^8+18x^4+9=x^4两边减去9x^49x^8+9x^4+9=-8x^4所以x^4/(x^8+x^4+1)=-9/8再问:标准答案是:1
x平方乘以(x-2-根号2)(x-2+根号2)((y-x)(y+x))分之一小用料:(ab+ac+bc)*2,大用料:(3ab+3ac+4bc)*2大比小多:(2ab+2ac+3bc)*2
x+1/x=4得x^2+2+1/x^2=16x^2+1/x^2=14x四次方加x平方加1分之x平方=x^2/(x^4+x^2+1)=1/(x^2+1+1/x^2)=1/15