x乘以(x^2-1)分之1的不定积分

（2x-5）/(x-2)(x-3)-1/(x-3)=（2x-5）/(x-2)(x-3)-(x-2)/(x-2)(x-3)=（2x-5-x+2)/(x-2)(x-3)=（x-3)/(x-2)(x-3)=

(1-x)^2/(x^2+4x+4)/(x-1)^2*(x^2+3x+2)/(x-1)=(x+1)/(x+2)(x-1)=(x+1)/(x^2+x-2)再问：是1-x的平方，不是（1-x）的平方再答：

两边除9^(1/x)3*(4/9)^(1/x)+(6/9)^(1/x)=23*(4/9)^(1/x)+(2/3)^(1/x)=2令a=(2/3)^(1/x)则3a²+a-2=0(a+1)(3

首先计算(x+3)/(x^2-1)乘以（x^2-2x+1）/(x^2+4x+3),分解因式可以得到(x+3)/(x+1)(x-1)乘以(x-1)^2/(x+3)(x+1),约分后等于(x-1)/(x+

原式=[(x+2)/x(x-2)-(x-1)/(x-2)²]*x/(x-1)(x-4)*(x-2)²=(x²-4-x²+x)/x(x-2)²*x/(x

=(x+1)/x*(2x)^2/(x+1)^2-(2/x^2-1)=4x/(x+1)-2/(x^2-1)=(4x^2-4x-2)/(x^2-1)再问：*和^是什么意思？

2X的平方+8X+8分之X的平方+2X+1除以(X+1)乘以X+1分之X+2=(x^2+2x+1)/(2x^2+8x+8)*1/(x+1)*(x+2)/(x+1)=(x+1)^2/2(x^2+4x+4

[(x^3-x)/(x^2-2x+1)]*(x-1)/x=[x(x^2-1)/(x-1)^2]*(x-1)/x=[x(x-1)(x+1)/(x-1)^2]*(x-1)/x=x+1=√2-1+1……（因

)【(x²-2x+1)/(x²-1)】÷【(x-1)/(x²+x)】=【(x-1）²/(x+1)（x-1)】÷【(x-1)/x(x+1)】=【(x-1）/(x+

∵x=-1/2∴2x=2×(-1/2)=-1

因为等于6,没有5得存在,所以y=z,6我们可以看出是2*3,你把8看出2的3次方,9看出3的平方,16看成2的4次方,加上y=z,可以得到5y-3x=1,2x-3y

原式=[3x/(x-1)-x/(x+1)]×[(x²-1)/x]={3x(x+1)/[(x-1)(x+1)]-x(x-1)/[(x-1)(x+1)]}×[(x-1)(x+1)/x]=[3x(

lim(x→0)cotx[2x/(1-x)]=lim(x→0)2x/[tanx(1-x)]x→0tanx与x价=lim(x→0)2x/[x(1-x)]=lim(x→0)2/(1-x)=2

(x^2-4y^)\(x+y)^2乘以2x(x+y)/(x+2y)=2x(x-2y)\(x+y)

克服困难,勇敢者自有千方百计,怯懦者只感到万般无奈.再问：。。。复制去Google翻译翻译结果

(x+1)分之1-(x²-1)分之1×(x+1)分之(x²-2x+1)=(x+1)分之1-[(x+1)(x-1)]分之1×(x+1)分之(x-1)²=(x+1)分之1-(

1乘以2分之x+2乘以3分之x+.+2012乘以2013分之x=2012(1-1/2+1/2-1/3+……+1/2012-1/2013)x=2012(1-1/2013)x=20122012/2013x

“x的平方-4x+4分之x-1乘以2x-2分之x的平方-4”数学表示式是：[(x-1)/(x-4x+4)]×[(x²-4)/(2x-2)]；原式=[(x-1)/(x-2)²]×{[

观察x/(1×2)=x/2而x-x/2=x/2则有x/(1×2)=x-(x/2)x/(2×3)=x/6而(x/2)-(x/3)=x/6则有x/(2×3)=(x/2)-(x/3)同理x/(3×4)=(x