输入某整数n,判断它是否被3整除,若能输出yes,否则输出no,要求用函数-搜答案-灵鹊做题网

///c语言的,#inlcudevoidmain(){inta;printf("pleaseinputanumber:\n");scanf("%d",&a);if(a%5）printf("thisnu

#includevoidmain(){inta,b,c;printf("请输入一个大于3的数\n");scanf("%d",&a);for(b=2;a>b==1;b++){c=a%b;if(c==0)

多的我就不说了,函数如下（你只需把下面的代码贴在intmain()之前就行了,然后在开头加一个头文件：#include）：boolisPrime(intx){if(x==1)return0;for(i

#includemain(){inty;scanf("%d",&y);if(y%400==0||y%4==0&&y%100!=0)printf("Yes.\n");elseprintf("No.\n"

(yearmod4=0)and(yearmod1000)||yearmod400=0

一个个试或者运用数论里的素性判定的知识

#include#includeintmain(){printf("请输入一个正整数：");intn1,n2;boolflag1=false,flag2=false;scanf("%d",&n1);n

#includemain(){inta;printf("ÊäÈëÒ»¸öÕý&

#includemain(){intn;printf("输入年份:");scanf("%d",&n);if(n%4==0&&n%100!=0||n%400==0)printf("闰年\n");else

#include <stdio.h>#include <math.h>int main(void){

PrivateSubCommandButton1_Click()DimnNumAsLongIfIsNumeric(TextBox1.Text)ThennNum=Val(TextBox1.Text)If

#include#includevoidmain(void){inti,j,k,f,z;scanf("%d",&i);if(i

vari,n:longint;b:boolean;beginreadln(n);b:=true;ifn

#includeusingnamespacestd;voidmain(){intn;cin>>n;if(n%2==0)cout

a(n+1)/an=3^(n+1)/3^n=3公比是3的等比数列

Subtest()OnErrorGoTo10n=InputBox("输入一个整数")MsgBoxIIf(nMod2=0,"你输入的是个偶数","你输入的是个奇数"):ExitSub10:MsgBox"

看看：http://hi.baidu.com/%D7%F6%B6%F8%C2%DB%B5%C0/blog/item/e0908bf1971e64de7831aa4c.html再问：小的看不懂

intmain(){charc;scanf("%c",&c);if(c=="a"||c=="e"||c=="i"||c=="o"||c=="u"||c=="A"||c=="E"||c=="I"||c=

#include"stdio.h"intmain(){ intn; &n

再问：lnn/n^2为什么小于根号n/n^2啊？再答：很容易证明啊，令f(x)=ln(x)-√x，然后求导f'(x)=1/x-1/(2√x)，当x>2时f'(x)