输入整数x和a,计算并输出下列分段函数f(x)的值

#includevoidmain(){inta,b;printf("Inputtwointegers:");scanf("%d%d",&a,&b);printf("和:a+b=%d\n",a+b);p

#include#includevoidmain(){floatx,y;cin>>x;if(x

1：#includeintmain(){intnum,sum=0;while(scanf("%d",&num)==1&&num>0){sum+=num;\x09}printf("结果为%d",sum)

首先C我长时间没碰了,但你的程序的问题还是能看出来的,还是看看书吧.main函数就不对,应是main(){程序主体}.if函数没有返回值,你的程序中没必要用这么多花括号,当if或else后只有一句条件

#include<stdio.h>int main(){\x09int x,y;\x09printf("输入x的值："); \x09sca

#includevoidmain(){inta,b;printf("pleaseinputtwonums:");scanf("%d%d",&a,&b);printf("%d%d\n",a/b,a%b)

基于c#的classProgram{staticvoidMain(string[]args){Console.WriteLine("Pleaseenteranumber");inta=int.Pars

我写了一个c语言的!#includemain(){inti,n,sum=1;scanf("%d",&n);for(i=1;i

print改成printf就可以了标准答案拿去吧除法进行的Int型的除法自己懂得#includeintmain(void){intnum1,num2;intx,y,z,k,j;printf("Ente

#includemain(){inta,b,c,d;printf("请输入第一个整数:");scanf("%d",&a);printf("请输入第二个整数:");scanf("%d",&b);prin

#includeintmain(void){\x09intnum,i,j,k,sum;\x09printf("输入一个三位整数!\n");\x09scanf("%d",&num);\x09i=num%

usingSystem;usingSystem.Collections.Generic;usingSystem.Linq;usingSystem.Text;namespaceCompare_Numbe

#include//希望对您有用#includeintmain(){intx,y;printf("Pleaseenterthenumber:");scanf("%d",&x);if(x

Dimi1AsIntegerDimi2AsIntegerDimi3AsIntegeri1=Val(InputBox("请输入第一个整数"))i2=Val(InputBox("请输入第二个整数"))i3

#include"stdio.h"#include"time.h"main(){inta[100],i,t,x,k=0;intm=1,n=100;printf("该数组元素有：\n");srand((

一看就是学习不用功的.有1+-1+2=2的式子吗?

#includevoidmain(){inta,b,c,d;printf("Pleaseinput3numbers,example,[1,2,3]:\n");scanf("%d,%d,%d",&a,&

inti,geshu=0,sum=0,a[100],aver;scanf("%d",&a[i]);for(i=0;i

#include#include#includeintmain(void){intn=0,sum=0;int*nums;printf("请输入整数个数：\n");scanf("%d",&n);nums

我不会啊啊