输入三个整数1,10,-6,求最大值为10,最小为-6,补充代
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输入两个整数的比较:#inlucevoidmain(){inta,b;scanf("%d,%d",&a,&d);if(a>b)printf("%d",a);elseprintf("%d",b);}输入
#includeintmain(){inta,b,c;printf("输入三个数");scanf("d%d%d%",acb,c);intt,k;t=a>b?a:b;k=t>c?t:c;printf("
#includeintmain(){inta,b;floatc;printf("请输入两个整数和一个实数\n");scanf("%d%d%f",&a,&b,&c);c=a+b+c;printf("这三
constn=10;vari,j,k,l:integer;ch:char;beginread(i);ch:='N';k:=0;forl:=2tondobeginread(j);if(i>j)and(c
#includevoidmain(){inta,b,c;intsum,max,min;doubleaverage;printf("请分别输入a,b,c三个整数的值(逗号隔开):");scanf("%d
先写个函数判断n1、n2、n3大小,假设n1再问:怎么弄出n1n2n3的大小啊再答://传入三个参数n1、n2、n3的引用,程序运行完后满足n1
a+b>cabs(a-b)再问:能编个完整的给我吗?谢谢。新手,看不懂啊……不胜感激再答:#includeinta,b,c;scanf("%d,%d,%d",&a,&b,&c);if(a>0&&b>0
#include“stdio.h"voidmain(){\x09inta,b,c,sum;\x09floatave;scanf("%d%d%d",&a,&b,&c);sum=a+b+c;\x09ave
#include#includeintmax(inta,intb,intc){c=c>(a=a>b?a:b)?c:a;returnc;}intmain(){inta,b,c;scanf("%d%d%d
页面代码请输入第一个数:请输入第二个数:请输入第三个数:计算三个数中最小的数是:js代码是functiongetnum(){varnumone=document.getElementById("tex
#includemain(){intm,n,p,t;printf("输入m,n,p的数值");scanf("d,%d,%d,&m,&n,&p");/*不知道你说的调整使得mp){t=m;m=p;n=t
#includeusingnamespacestd;intmain(){\x09inta=0,b=0,c=0;\x09coutb>>c;\x09if(a>b&b>c)\x09{\x09\x09cout
用什么语言写再问:C语言再答:#includemain(){inti,a[10],t,max;for(i=0;i
#include"stdio.h"intmain(){intn,m,i,j,x,s;doubleave[100];scanf("%d",&n);for(i=1;i
#includevoidmain(){inta,b,c,min,max,cha;scanf("%d%d%d",&a,&b,&c);min=a;max=a;if(b>max){max=b;}if(bma
题意不是太清楚你是要输入还是输出?10个数显2排第二排一定不是3:3十个数没有范围、正负限定吗?
intvalues[10];intinput(){inti=0;printf("input10numbers:\n");for(i=0;i{scanf("%d",&values[i]);}return
你叫唤的是指针指向,但目标abc的值没有改变#includemain(){inta,b,c,n;int*p1,*p2,*p3;scanf("%d%d%d",&a,&b,&c);p1=&a;p2=&b;
#includevoidmain(){inti1,i2,i3,sum,avg;scanf("%d",&i1);scanf("%d",&i2);scanf("%d",&i3);sum=i1+i2+i3;
intnum1,num2,num3;floataverage;printf("pleasenum1,num2,num3:\n");scanf("%d,%d,%d",&num1,&num2,&num3)