输入一个3位正整数.分别输出他的个位十位百位
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voidmain(){intn=-1;while(n
//z2.cpp:定义控制台应用程序的入口点.//#include"stdafx.h"#include#includeusingnamespacestd;voidReverse(int&m)//m为4
#includeintmain(){inti,k,n,t;doubleans;scanf("%d",&n);ans=0;t=1;k=1;for(i=1;i再问:输入输出示例Entern;3sum=0.
main(){longinta;intb,c,d,e,f;scanf("%ld",&a);while(a>=1&&a=1&&a/10000=1&&a/1000=1&&a/100=1&&a/10=1&&
intmain(){intn,n1,n2,n3,n4;cin>>n;n1=n/1000;n2=(n%1000)/100;n3=(n%100)/10;n4=n%10;n=n1+10*n2+100*n3+
程序中的ab不知道做什么用的.pow(x,y)中x,y值反了,跟踪发现c=pow(x,-1)值为0这里因为c是整型,自动忽略小数位,值为0所以sum=sum+a*c;得到sum=0恒成立#includ
#includevoidmain(){intx,a,b,c;scanf("%d",&x);a=x/100;b=x/10%10;c=x%10;x=c*100+b*10+a;printf("%d",x);
#includeintmain(){intn;scanf("%d",&n);do{printf("%d",n%10);}while(n/=10);printf("\n");return0;}
#includevoidmain(){inta,i=0,b[3];printf("inputathreebitnumber\n");scanf("%d",&a);if(a>=100&&a=0;j--)
这个是第一种:#includevoidmain(){inti,j=1,N;printf("请输入N的值:\n");scanf("%d",&N);for(i=1;i
#include#includeintmain(){intoldnum;intnewnum=0;inttemp;printf("pleaseinputnumber\n");scanf("%d",&ol
能够把题目描述得清楚一些,看不明白啊?或者加个输入输出的样列也好啊.如果你描述清楚,我直接给你源程序.
#includeintmain(void){longintx;inty,i=1;printf("请输入一个不超过100000的整数:");//99999||x
#includeintmain(){intn,i;doublesum=0;printf("Entern:");scanf("%d",&n);for(i=1;i
#include#includeintmain(){doublea=1,b=1;doubles=0;inti,n;scanf("%d",&n);for(i=1;i
可以是可以,不过太麻烦了,见下面的代码#includeintmain(){inta,b[5],s=0;scanf("%d",&a);while(a){b[s++]=a%10;a/=10;}printf
PrivateSubCommand1_Click()d=Val(Text1)Print100*(dMod100)+Int(d/100)EndSu
#include"math.h"#includeusingnamespacestd;#defineM4voidmain(){intnum,p[M],i;cout
#includemain(){intn,sum=0;scanf("%d",&n);for(inti=0;i
#include#defineMAXN20intmain(){intn,t,k=0;intia[MAXN];printf("请输入一个整数:");scanf("%d",&n);while(t=n%10