解方程3X-6=X 2
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![解方程3X-6=X 2](/uploads/image/f/7208100-36-0.jpg?t=%E8%A7%A3%E6%96%B9%E7%A8%8B3X-6%3DX+2)
(3+X)x2=9(3+X)=9÷23+X=4.5X=4.5-3X=1.5
两边同乘x^2-1.3-3x=x^2-1,x^2+3x-4=0.(x+4)(x-1)=0.x=-4或x=1
设(x²-1)/(x²+2x)=t则8t+3/t=118t²-11t+3=0(8t-3)(t-1)=0解得t=3/8或t=11.t=3/8(x²-1)/(x
后面的x²+11x-708有误吧!再问:没有题目就这样能不能帮我再答:那我就试试:原式为:1/x2+x+1/x2+3x+2+1/x2+5x+6+1/x2+7x+12+1/x2+9x+20=5
2/(x2-x)+6/(1-x2)=7/(x2+x)2/x(x-1)-6/(x-1)(x+1)=7/x(x+1)[x*(x-1)*(x+1)]*[2/x(x-1)-6/(x-1)(x+1)]=[7/x
△=(-6)2-4×4×(-3)=60,x=6±2212×4=3±214,所以x1=3+214,x2=3−214.
3/x2=1/x2-x即3*2-3x=x*22x*2=3Xx=0(舍去)x=3/2
2x(x-3)-(x+6)(x-3)=x²+12提取x-3(2x-x-6)(x-3)=x²+12(x-6)(x-3)=x²+12x²-9x+18=x²
x^2-3x-1=0a=1b=-3 c=-1△=b^2-4ac=3^2-4*-1=13两个根为,所以X1=(3+根号13)/2 X2=(3-根号
原式可化为1/(x+1)(x-3)+2/(x-3)((x+2)+3/(x+1)(x+2)=0两边同乘以:(x+1)(x+2)(x-3)得:(x+2)+2(x+1)+3(x-3)=0(x≠-1,x≠-2
等式两边同时乘以(x+3)(x-2)(x+2)就可以去分母了
7/(X2+X)+3/(X2-X)=6/(X2-X),去分母,等式两端同时乘X(X+1)(X-1):7(X-1)+3(X+1)=6(X+1),7X-7+3X+3=6X+6,7X+3X-6X=6+7-3
2x+5x+3+4-x/2+2x+x-2=019x/2=-5x=-19/10检验:带入x是、原式=0
(x2-x)=3(x2+x)x2-x=3x2+3xx2-3x2-x-3x=0-2x2-4x=0-2x(x+2)=0x1=0x2=-2
容易得X=5是其中一个解,首先分母不能等于0,所以X不等于0,3,且X2-7X+H不等于0.然后X2-3X+2=X2-7X+H,解的X=(H-2)/4所以X=5或者X=(H-2)/4.限制H的取值不能
7/(x+x2)-3/(x-x2)=6/(x2-1)两边同乘以x(x+1)(x-1),得7(x-1)+3(x+1)=6x7x-7+3x+3=6x10x-6x=3-74x=-4x=-1经检验x=-1是增
令x²+x=t原方程变为t+1=6/tt²+t-6=0(t+3)(t-2)=0则t=2或-31)x²+x=2x²+x-2=0(x+2)(x-1)=0x=-2或x
两边乘x(x+1)(x-1)2(x-1)+3(x+1)=4x2x-2+3x+3=4x5x+1=4xx=-1经检验,x=-1时分母x+1=0增根,舍去方程无解
x²+x-1/(x²+x)=3/2两边同时乘以(x²+x)得:(x²+x)²-1=3(x²+x)/22(x²+x)²-3
(x-4)/(x²+x-2)=1/(x-1)+(x-6)/(x²-4)(x-4)/(x-1)(x+2)=1/(x-1)+(x-6)/(x-2)(x+2)(x-4)(x-2)=(x-