若X^2-3Y-5=0,側6Y-2X^2-6=?

来源:学生作业帮助网 编辑:作业帮 时间:2024/06/16 13:31:44
若X^2-3Y-5=0,側6Y-2X^2-6=?
若(5X+2Y-12)(5X+2Y-12)+|3x+2y-6|=0,则2x+4y=?

因为(5X+2Y-12)^2+|3x+2y-6|=0,其中加号两边的两个数都是大于等于0的,所以可以列出5x+2Y-12=03X+2Y-6=0解得X=3,Y=-1.5,所以2x+4y=0

6(x-y)-2(x+y)=14 3(x-y)+(x+y)=5

设x-y=mx+y=n则6m-2n=143m+n=5解得m=2n=-1即x-y=2x+y=-1解得x=1/2y=-3/2

已知X,Y,满足(X+3Y)(X-3Y)=-10(Y^2-6/5)和2X(Y-1)+4(1/2X-1)=0

很多数学符号,还是写出来方便.

若(x*x+y*y)(x*x+y*y)-4x*x*y*y=0,求代数式(x*x+5xy+y*y)/(x*x+2xy+y*

(x*x+y*y)(x*x+y*y)-4x*x*y*y=(x^4-2x^2y^2+y^4)=(x^2-y^2)^2=0x^2=y^2x/y=±1(x*x+5xy+y*y)/(x*x+2xy+y*y)=

(1)已知x+y=6,x²-y²=5,求x-y的值(2)若x+y=3,x²+y²

(1)已知x+y=6,x²-y²=5,x^2-y^2=(x+y)(x-y)=5x-y=5/(x+y)=5/6(2)若x+y=3,x²+y²=5(x+y)^2=3

若|2x-y+5|+(x+2y-4)的平方=0,则(2x-y)的三次方-(x-3y)(y-2x)的平方

∵|2x-y+5|+(x+2y-4)的平方=0∴2x-y+5=0,x+2y-4=0∴2x-y=-5,x+2y=4x-3y=-9则(2x-y)的三次方-(x-3y)(y-2x)的平方=(-5)^3-(y

若5x+3y=3x+4y=x+2y+6,则x+y=___

3x+4y=x+2y+62x-x+4y-2y=62x+2y=6x+y=6/2x+y=3

若4x-3y-6z=0,x+2y-7z=0,求代数式5x*5x+2y*2y-z*z/2x*2x-3y*3y-10z*10

题目设置挺好的不会很变态,没什么难度由4x-3y-6z=0,x+2y-7z=0,可以解得x=3z,y=2z,将它代入代数式5x*5x+2y*2y-z*z/2x*2x-3y*3y-10z*10z=(25

若3x-5y=0,则x+y/x=(),x-y/y=(),2x-3y/2x+3y=( )

3x-5y=0,则x+y/x=(8/5),x-y/y=(2/3),2x-3y/2x+3y=(1/19)因为3x-5y=0所以3x=5y设x=5,y=3,可以解得3x-5y=0,则x+y/x=(8/5)

若x,y互为相反数(y≠0),则2x+5+2y+3x/y=____

天啊,小朋友很简单因为x,y相反数,所以,2x,2y就抵消了,3x/y呢,就变成了-3,5-3=2,所以等于2

若|5x+2y-12|+(3x-2y-6)平方=0,则x+2y=?

绝对值和平方大于等于0,相加等于0,若有一个大于0,则另一个小于0,不成立.所以两个式子都等于0所以5x+2y-12=0(1)3x-2y-6=0(2)(1)-(2)2x+4y-6=02x+4y=6x+

y-3x=2,y-5x=4,y-7x=6,y-9x=8,y-11x=0方程组,

最后一个应该是:y-11x=10吧这样解就是X=-1,Y=-1否则无解

已知x-5y=0(y≠0),则代数式2x-3y/3x+6y

x-5y=0x=5y所以(2x-3y)/(3x+6y)=(10y-3y)/(15y+6y)=7y/21y=1/3

若(x-y)/(x+y)=3 则(x+2y)/(6x-7y)等于

若(x-y)/(x+y)=3那么x-y=3(x+y)x-y=3x+3y故x=-2y所以(x+2y)/(6x-7y)=(-2y+2y)/(6*(-2y)-7y)=0如果不懂,请Hi我,祝学习愉快!

若|5x-2y-3|+(x+6y-11)X(x+6y-11)=0成立,求x,y的值,

设|5x-2y-3|=a,x+6y-11=b,则由题得,a+b*b=0且啊a>0.b*b>0,所以,a=0,b=0所以得5x-2y-3=0x+6y-11=0联立求解为x=5/4,y=13/8

若2x-3y+4=0则x(x*x-1)+x(5-x*x)-6y+7

x(x*x-1)+x(5-x*x)-6y+7=-x+5x-6y+7=2(2x-3y)+7=2*(-4)+7=-8+7=-1再问:能在写详一点吗-x+5x-6y+7再答:x(x*x-1)+x(5-x*x

若4x^2-4x+9y^2-12y+5=0求6x+2/3y

[(2x)²-4x+1]+[(3y)²-12y+2²]=0(2x-1)²+(3y-2)²=02x-1=0且3y-2=0x=1/2,y=2/36x+2/

若|5x+2y-12|+(3x+2y-6)(3x+2y-6)=0,则2x+4y=

|5x+2y-12|+(3x+2y-6)(3x+2y-6)=0|5x+2y-12|=0、3x+2y-6=0∴5X+2Y=12、3X+2Y=6解得,X=3,Y=-3/2则2x+4y=6-6=0.

已知x^3+xy^2+x+x^2y+y^3+y=0,求5x-6y/3x+4y的值.

(x³+y³)+(x²y+xy²)+(x+y)=0(x+y)(x²-xy+y²)+xy(x+y)+(x+y)=0(x+y)(x²-

若2x-3y=0,求5x+4y/3x-2y

2x-3y=02x=3yx=1.5y5x+4y/3x-2y=7.5y+4y/4.5y-2y=11.5y/2.5y=4.6