编程求最大公约数 vf

clearinput"请输入第1个数："toainput"请输入第2个数："tobc=min(a,b)dowhilec>0ifa%c=0andb%c=0s=cexitendifc=c-1enddo?"

store0tosume,sumofori=100to1000ifi%2=0sume=sume+i&&偶数累加elsesumo=sumo+i&&奇数累加endifnext"100~1000偶数累加和=

clears=1input"请输入n的值："tonfori=2tonk=(-1)^im=k/is=s+mendfor"s=1+1/2-1/3+1/4+...+1/n",s

#includeintmax(intm,intn);intmin(intm,intn);intx,y;//x为最大公约数,y为最小公倍数voidmain(){intm,n;coutm>>n;cout

clears=0input"n="tonfori=1tonk=1forj=1toik=k*jendfors=s+kendfor?"s=1!+2!+3!+4!……+n!=",s

clears=0fori=1to100ifi%3=0s=s+iendifendfor"100以内所有能被3整除的整数的和是：",s

http://zhidao.baidu.com/link?url=wyic3NEB45i2K9YZE2SpNiAV4aD7rZHpluBlyF76zg0n_8wr1t6-KOYm6eYY23KqG5n

（1）题程序如下：settalkoffs=0i=1dowhilei

1.clearInput"请输入圆的半径"toc=3.14*r*2s=3.14*r*r?"圆的周长为：",c,"圆的面积为:",sreturn2.clearinput"请输入计程车公里数"towifw

clears=0fori=1to100ifi%30ifi%2=1s=s+iendifendifendfor"1至100之间非3的倍数的所有奇数之和为：",s

inputnS=0Fori=1tons=s+i+iENDFORss=SQRT(S)

clearinput"请输入第1个数："toainput"请输入第2个数："tobc=max(a,b)dowhile.t.ifc%a=0andc%b=0s=cexitendifc=c+1enddo"它

#includeintmain(){inta,b,m,n,t;printf("请输入两个正整数,两整数间请按逗号:\n");scanf("%d,%d",&m,&n);if(m

mModn=rr=mModn

void main(){int m=0,n=0,i,imax=0,imin=0,gongyue=0;printf("请输入m和n");scanf(&quo

main(){intp,r,n,m,temp;printf("Pleaseenter2numbersn,m:");scanf("%d,%d",&n,&m);//输入两个正整数.if(n

clears=0fori=2to1000step2s=s+inext或者clears=0fori=1to1000ifi%2==0s=s+iendifnext

clears=0fori=1to100step2s=s+iendfor"100以内奇数之和是：",s

clearinput"n="tons=1fori=1tons=s*iendfor"n!=",s

*VF编程π/4=1-1/3+1/5-1/7+.公式求πCLEARn=100000p=0FORi=1TOn\x05IFMOD(i,2)=0\x05\x05p=p-1/(2*i-1)\x05ELSE\x