编程从键盘输入n求1 2 3 n的值

floatmax(floata[])//求数组a中的最大值函数{floatmax=0;for(inti=0;imax)max=a[i];//将数组a中比max大的元素存入max中returnmax;}

#include"stdio.h"doublef(intk,intn){doublei=n;intj;for(j=1;j再问：i=f(k,n-1)+i;这句不对再答：程序写错了，应该是这样#inclu

#includemain(){intm,n,k,j,s,t;printf("pleaseinputthenumberofm,n,k\n");scanf("%d",&m);scanf("%d",&n);

这个是那一章的全部答案1．设有如下两组数据：(1)1,3,5,2,4,18,50,25(2)5,27,30,35,60,41,87,33编写一个程序,把上面两组数据分别读入两个数组中,然后把

intn,sum=0;cin>>n;for(inti=1;i

#include#include#includeintmain(){intn;intsum1=0;intsum2=0;scanf("%d",&n);int*p;p=(int*)malloc(n*n*s

//所谓模块化,说得通俗点,就是不断地嵌套调用函数来实现.且看下面：#includeusingnamespacestd;intf(intn)/*定义递归地求阶乘的函数f*/{if(n==0)retur

input"n="tons=0fori=1tons=s+iendforcancel

楼主你好!根据你要求实现如下#include<stdio.h>int fun(int n){ if(n>0)return n*fun(n-1)

#include#includeintfactorial(intn);doublefact(intn);doublepower(intn);intmain(){inti,j;\x05doubleff=

程序的实现的是这样的,先设置一个文本框,用于n值的出入.再设置一个命令按钮用于求解.代码如下：PrivateSubCommand1_Click()DimnAsInteger,iAsInteger,mA

#includevoidmain(){longi,n,num=1,result=0;printf("Pleaseinputanum:");scanf("%ld",&n);for(i=1;i

1,#includelongfoo(intn){if(1==n)return1;returnn*f(n-1);}intmain(void){intm,n,k;scanf("%d%d%d",&m,&n,

#includemain(){inti,j,n,k,t;doublesum=2;printf("inputanumber:\n");scanf("%d",&n);j=2;k=1;for(i=1;i再问

要是n较小,你可以拿笔算算,只能利用BASIC语言软件来计算快一点啊设S=n!则程序如下：INPUTni=1S=1WHILEi

#includevoidmain(){inti,j,n;printf("请输入n的值：\n");scanf_s("%d",&n);for(i=1;i

PrivateSubCommand1_Click()DimiAsInteger,jAsInteger,nAsIntegerDimsum1AsLong,sum2AsLongn=inputbox("请输入

intmain(){intn=0;inti=0;intsum=0;scanf("%d",&n);for(i=2;i

#includeintmain(){intn,i,sum=0,temp=1;scanf("%d",&n);for(i=n;i>0;i--){sum+=temp*i;temp++;}printf("%d

classOddSum//定义类{publicstaticvoidmain(Stringargs[])//main方法{intsum=0;//定义一个整形变量for(inti=1;i