log3(log2x)=0,则x-1=( )-搜答案-灵鹊做题网

由条件知，log3（log2x）=1，∴log2x=3，∴x=8，∴x-12=24．故选C

log5tan45°=log51=0log7[log3(log2x)]=0log3(log2x)]=1log2x=3x=8x^(-1/2)=8^(-1/2)=√2/4

log3(log2x)=1log2x=3x=2³x=8

∵log3[log4（log2x）]=0，∴log4（log2x）=1，∴log2x=4，即x=24=16，故答案为：16

楼主,很高兴为您因为只有log7(1)才等于0,所以括号里必须等于1.再问：对不起我还是不懂我对数是自学的能不能再用通俗易懂的方式讲一次再答：对数就是指数反过来，7的0次方等于1，则log7（1）=0

log7[log3(log2x)]=0所以log3(log2x)=1所以log2x=3所以x=8求的式子没看懂,自己算算

4

根据题意得：log5（log2x）=1,所以log2x=5,所以x=2^5=32.亲,您的采纳是我的动力,

log1/2(log2x)=1--->log2x=1/2-->x=2^(1/2)log1/3(log3y)=1--->log3y=1/3-->y=3^(1/3)x^6=8再问：x^6=8

log7[log3(log2x)]=0=log7(1)log3(log2x)=1=log3(3)log2x=3x=2³=8

log4[log3(log2x)]=0=log4(1)所以log3(log2x)=1=log3(3)所以log2(x)=3x=2³=8x^(-1/2)=1/√8=√2/4

解log11[log3(log2(x))]=011^0=log3[log2(x)]=13^1=log2(x)=32^3=xx=8∴x^(-1/2)=8^(-1/2)=√2/4

log3(log2x)=1log2x=3x=2^3=8log4x=log4(8)=3/2

log3(log2x)=1log2x=3^1=3x=2^3=8x^(1/2)=√8=2√2

分母不能为零,log后上方得为正,故选C

log7【log3（log2x）】=0log3[log2(x)]=7^0=1log2(x)=3^1=3x=2^3=8

1、由题知log3(log2x)=1∴log2x=3∴x=2^3=8∴x^(-1/2)=(√2)/42、∵易得3^a>1；3√a∴3√a又∵a^9∴a^3∴a^3<3√a<3^a

1/2根3

∵log2[log12(log2x)]＝log3[log13(log3y)]＝log5[log15(log5z)]=0，∴log12(log2x) ＝log13(log3y)=log15(l

/>希望能够帮到你好像弄错了,log2^(log3^x)中2是底数吧?如果是这样应该这么算：log2^(log3^x)=0,则log3^x=1,x=3log3^(log4^y)=0,则log4^y=1