lim xsin1÷x-搜答案-灵鹊做题网

x^2-1=(x+1)(X-1)x^2-2x+1=(x-1)^2第一项为（X+1）/(x-1)第二项为-x(x+1)so最后-1/x(x-1)

[（x+2）/（x*x-2x）-（x-2）/（x*x-4x+4）]/[(x-4)/x]=[（x+2)/x(x-2)-(x-2)/(x-2)²]/[(x-4)/x]=[(x²-4-x

=（x+1）(x-1)(x+1)x-1--------------÷------×-----(x-1)^2(x-1)x+1=x+1---x-1

(x+1-1/1-x)÷(x-x²/x-1)=[(x+1)+1/(x-1)]×[-(x-1)/x(x-1)]=(x²-1+1)/(x-1)×(-1/x)=-x/(x-1)(x-4/

计算：（1+1/x）·x²-2x+1/x²-1；=（x+1）/x×(x-1)²/(x²-1)=(x-1)/x;（x²/x-1-2x/1-x）÷x/x-

x-2/x-1÷(x+1-3/x-1)

解题思路：分式的混合运算，按照分式运算法则进行计算。解题过程：

先化简去掉中括号：(1-x+x-1/x)÷(1-1/x-1)再化简：(1-1/x)÷(-1/x)=(1-1/x)x(-x)=1-x

(2x-6)/(x²-4x+4)÷(3-x)/(x²+6x+9)×(2-x)/(x+3)=2（x-3)/(x-2)^2X(x+3)^2/(3-x)X(2-x)/(x+3)=2（x-

(x²-4x+4)/(x²-2x)÷(x-4/x)=(x-2)²/[x(x-2)]÷[(x²-4)/x]=(x-2)²/[x(x-2)]÷[(x+2)

原式=2x(x-2)/(x+2)×x(x+2)/(x-2)²×3(x-2)/x=6x当x=√3/2时原式=3√3

1.xsin(1/x)=0啊,sin(1/x)=sin无穷大属于[-1,1],乘以无穷小当然是02.互为反函数的图形都关于直线y=x对称,你理解对了

1.(x^3-3x^2)/(x^2+5x+6)÷(x^3-9x)/(x^2+2x-3)*(x+2)/(2x)=x^2(x-3)/(x+2)(x+3)*(x+3)(x-1)/x(x+3)(x-3)*(x

解1：原式=x(x-1)/(x+1)*(x+1)/x=x-1解2：原式=(x+3)^2/(x+3)(x-3)*(x-3)/(x+2)=(x+3)/(x-3)*(x-3)/(x+2)=(x+3)/(x+

2x/(x-2)(x+1)÷(1－x/x+1)-x²+2x/x²-4?=2x/(x-2)(x+1)×(x+1)/(1-x)-x(x+2)/(x+2)(x-2)=2x/(x-2)(1

=【3x(x+1)-x(x-1)]/(x+1)(x-1)×(x+1)(x-1)/x=(3x²+3x-x²+x)/x=4

[3x/(x+2)-x/(x-2)]÷2x/(x^2-4)分子分母同时乘以x²-4=[3x(x-2)-x(x+2)]/2x=(3x²-6x-x²-2x)/2x=(2x&#

①x²-4／x²-4x+3÷x²+3x+2／x²-x=(x²-4)/(x²-4x+3)÷(x²+3x+2)/(x²-x)

x(2-1/x)+x/(x^2-2x)÷(3-x)/(x^2-4)=x((2x-1)/x)+x/(x^2-2x)x(x^2-4)/(3-x)=(2x-1)+(x+2)/(3-x)=(7x-3-2x^2

你的括号丢得太多了,我猜猜猜1、实在猜不出来,哪里该有括号2、2X/(2X-1)+X/(X-2)=2[2X(X-2)+X(2X-1)]/(2X-1)(X-2)=22X^2-4X+2X^2-X=4X^2