用c语言打印出1000-9999所有的回文数.
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/15 06:03:47
在for(j=1;j
#include"stdio.h"#defineN5voidmain(){inti,j;for(i=0;i
#includevoidmain(){inta;printf("输入一个三位数");scanf("%d",&a);printf("百位:%d十位:%d个位:%d\n",a/100,a/10%10,a%
#includemain(){inta,b,c;scanf("%d,%d,%d",&a,&b,&c);printf("%d\n",(a>b?a:b)>c?(a>b?a:b):c);}
#include//头文件#include//头文件intmain(){intn;//定义一个数作为行数printf("n=");//输出提示输入的信息scanf("%d",&n);//输入行数for
代表的意思是负无穷!再问:用什么表示呢?比如我返回的是double类型,变量a是a==-1.#ING?再答:在头文件里面。你可以找到对于浮点数各种边界值的宏定义。#defineDBL_MIN2.225
我可以给你写出代码,#includeintmain(){inti,j,k,n;scanf("%d",&n);for(i=1;i
//#includeintmain(){inti,j,n;printf("输入行数(正数):");do{scanf("%d",&n);}while(n
#includevoidmain(){\x09inti,j,k;\x09for(i=1;i
#include#include#defineN9//范围可以是1到9intmain(){constchar*str="";intnum[20];inti;for(i=1;i
#includeintmain(void){intx,y,num;printf("请输入正方形的边长:");scanf("%d",num);for(x=0;xfor(y=0;yif(x==0||y==
拿去交差吧.!完美.#includeintmain(){inti,j,n;scanf("%d",&n);for(i=1;i
#include"stdio.h"main(){inta[20][20],i,j,k,p=1,m,n;while(p==1){printf("Entern(n=1--19):");scanf("%d"
#includevoidmain(){inti,j,k;for(i=1;i再问:这样子?再答:应该是吧
#include "stdio.h"int main(){ int n,i,j;
#include#definetrue1voidprint(charcType,intiRow,intiColumn,charcMark){inti,j;if(cType=='A'){for(i=0;
#includevoidfun(inta[][34],intn){inti,j;for(i=0;i
#include#include#includevoidmain(){inta[20][20];intk;intn,i,j;do{coutn;}while(n>20||n%2==0);i=n/2;j=
#includevoidmain(){inti,j;for(i=1;i
#includeintmain(){\x09inti,j,h,k;\x09scanf("%d",&h);\x09for(j=0;j