求隐函数的导数y^2=cos(x y)-搜答案-灵鹊做题网

y=x-sinx/2cosx/2y=x-sin(x/2)cos(x/2)=x-(1/2)sinxdy/dx=1-(1/2)cosxy=x^3+3^xy=x^3+3^x,y'=3x^2+3^xln3

(1)2/x^2导数为:(0-4x)/x^4=-4/x^3所以y=(2/x^2)-1的到数为-4/x^3(2)sinx导数为cosxcos^2x=(1+cos2x)/2因此cos^2x导数为-sin2

y=cos(x+y)dy/dx=dcos(x+y)/d(x+y)·d(x+y)/dx,链式法则dy/dx=-sin(x+y)·(1+dy/dx)dy/dx=-sin(x+y)-sin(x+y)·dy/

y=coa(x+y)dy/dx=-sin(x+y)·(1+dy/dx)dy/dx=-sin(x+y)-sin(x+y)·dy/dx[1+sin(x+y)]dy/dx=-sin(x+y)dy/dx=-s

y=cos^2x+cosx^2y'=2cosx(-sinx)+(-sinx^2)*2x=-2sinxcosx-2xsinx^2=-sin2x-2xsinx^2

1.将cos(2x-π/3)看成整体√cos(2x-π/3)的导数是1/[2√cos(2x-π/3)]将2x-π/3看成整体cos(2x-π/3)的导数是-sin(2x-π/3)2x-π/3的导数是2

对等式两边求导,得y'=-sin(xy)*(y+xy')y'=-ysin(xy)/[xsin(xy)+1]

y=cos(x+2)y'=(x+2)'（-sin(x+2))=-sin(x+2)lim(△x→0)[cos(x+△x+2)-cos(x+2)]/[(x+△x+2)-(x+2)]=lim(△x→0)-2

设p=sin(nx),q=(cosx)^n则p'=ncos(nx),q'=cos(x+nπ/2)∴y'=p'q+pq'=ncos(nx)·(cosx)^n+sin(nx)·cos(x+nπ/2)

y'=acosby'=-asin

y=1+1/2*sinxy'=1/2*cosx

先对cos求导=-sinx^2再对x^2求导=2x所以y'=-2x*cosx^2

y=(1-cos^2X)^4=(sin^2x)^4=(sinx)^8y’=8(sinx)^7(sinx)'=(sinx)^8cosx

y'=-sin(4-3X)*(-3)=3sin(4-3X)

答：y=cos(-2x+π/4)y=cos(2x-π/4)y'(x)=-2sin(2x-π/4)

复合函数求导y'=[cos（sinx）]'=sin(sinx)·（sinx）‘=sin（sinx）·cosx

y等于负4被sin2x

答案没有错.Y'=(COS^3（1—2X）)'=3*COS^2（1—2X）*（COS（1—2X））'=3*COS^2（1—2X）*（-sin（1—2X））*(1—2X)'=3*COS^2（1—2X）*

y=xsinx(x/2-π/2)cos(x/2+π/2)=-xsin(π/2-x/2)(-sinx/2)=xsinx/2cosx/2=1/2xsinxy'=1/2[sinx+xcosx]