c语言输入十个数,求出平均分和最高分

#includeintmain(){inta,b;scanf("%d%d",a,b);if(a>b)printf("%d",a);elseprintf("%d",b);return0;}

定义四个变量intn,max,min,sum;先读一个数据scanf("%d",&n);sum=max=min=n;再循环9次,输入9个数,同时,累加,比较大小for(i=0;imax)max=n;i

#include/*含有scanf和printf必需的头文件*/voidmain(){inta[20],i,max;/*定义变量*/for(i=0;i

求和应当是：#include#includemain(){inti,up=0,down=0,data[10];for(i=0,i0)up+=data[i];elsedown+=data[i];}pri

用数组main(){inti,m=0,n=0,a[10];printf("input10numbers:\n");for(i=0;i

voidmain(){inti=0,sum=0,max,num;floatavg=0.0;for(i=0;imax)max=num;}sum=sum+num;}avg=sum*1.0/20;print

#include#include#includevoidmain(){inti,j,t,max,a[5];for(i=0;i

#includevoidmain(){intm,n,i,j,k;intsum=0;scanf("%d%d",&m,&n);for(i=m;i

#includevoidmain(){inta[10];inti,n=0;floatsum=0;for(i=0;i

把5个成绩加起来,除与5就得平均成绩.如：intscore[5]={90,80,80,95,87};intsum;sum=0;floatavg=0;for(inti=0;i

# include <stdio.h>#define N 10//元素个数void sort(int a[], int

/*C语言输入十个数,判断正数的个数以及它们的平均值*/#include"stdio.h"voidmain(){floatave=0;intval;inti;intn=0;floatsum=0;pri

#includevoidmain(){inta[10],i=0,j=0;intmax1=0,max2=0,tmp=0;printf("Pleaseinputnumbers:");for(i=0;i再问

#includemain(){floata[10],da,xiao,m=0;inti;printf("pleaseinput10data:");for(i=0;i

#include<stdio.h>intmain(void){ inti,j,k; inta[10]; intmin=0,max=0; for(i=

设一个变量,将avg(x,temp)的值传给它;

财富值!

一楼基本上是对的,不过循环这些有错,还是必须加上循环的中止条件,调试无误代码如下：#include"stdio.h"intmain(){\x09signedintn;//因为要与-1比较,所以n定义为

#includevoidmain(){inti,arr[10];intsum=0;intcount=0;doubleavg=0;for(i=0;i!=10;++i){scanf("%d

#include#defineNUM20voidmain(){longn;intdata[NUM]={0},len=0;scanf("%d",&n);do{data[len++]=n%10;n/=10