c语言求和程序1 (1 2) (1 2 3)-搜答案-灵鹊做题网

#includemain(){inti=1,j=1;intsum=0;for(j;j

楼上两位的代码可能有点小问题s += m*m+1/m;改成s += m*m+1.0/m;再问：您好，请您帮忙写一个完整的编程好么？谢谢了再答：#include&

#include#include#includevoidsort(int*p,intn){int*a,*b,t;for(a=p+1;a=a;--b)if(*(b-1)>*b){t=*(b-1);*(b

1编程1.1打印出以下图案** * ** * * * ** * * * * *

//VC6.0编译运行通过//求和s=1!+3!+5!#include//求阶乘函数intf(intn){if(1==n){return1;}returnf(n-1)*n;}//main函数intma

#includemain(){\x09intm,sum=0;\x09for(m=1;m

/*求任意两个整数m,n之间自然数之和*/#includevoidmain(){inti=0;longsum=0;while(i

从上到下分别为：（有些地方我没加分号...请自行判断）inttk=ia[j]

输入两个整数,中间空格：#include<stdio.h>main(){\x09int a,b;\x09printf("Input a,b:\n")

你好! hehe的函数内容改了,你对照原来的程序看看吧,满意请采纳#include<stdio.h>#include<math.h>

#includeintmain(){intn,i;while(scanf("%d",&n)!=EOF)/使用EOF/{longsum=0;for(i=1;i

#includevoidmain(){inti,j,sum=0;for(i=1;i

#includeintmain(){\x09inti,sum=0;\x09for(i=1;i

#includevoidmain(){inti,n;floats;scanf("%d",&n);i=1;s=0;if(i

#include"Stdio.h"intmain(void){inti,j;for(i=5;i>0;i--){for(j=1;j

#include <stdio.h>void main(){ int i, j;

#include <stdio.h>int main(){int a,b;scanf("%d%d",&a,&b);prin

#include<stdio.h>void main(){\x09int i, n, sum = 0;\x09int

#include <stdio.h>void main(){ int n;//n没声明int i=1,sum;sum=0;//sum没初始

#include#includeintmain(void){\x05intm;\x05scanf("%d",&m);\x05while(m--){\x05\x05intn,i;\x05\x05doub