按每行4个元素输出数组b.

inta[30];//存入就不需要写了吧?intb[30];intatb=0;for(inti=0;i

#include#include#includevoidavg(inta[],intn,doubleb[]){inti,j;for(i=0;i

祝你学习愉快!#include#defineN20intmain(){//声明被调用函数!voidmax(intb[],intn);voidmin(intb[],intn);voidaver(intb

#include#include#includevoidmain(){inti,t,temp;inta[50];srand((unsigned)time(NULL));for(i=0;i

PrivateSubCommand1_Click()dimi,a(),basintegerfori=21to1000ifimod21=0thenb=b+1redimpreservea(b)a(b)=i

#includemain(){inta[10];inti;for(i=0;i

main(){inta[20],b[5],i;for(i=0;iscanf("%d",&a[i]);for(i=0;i{b[i]=(a[5*i]+a[5*i+1]+a[5*i+2]+a[5*i+3]+

voidrevIntArr(intarr[],intlen){inti=0,j=len/2-1,temp;for(;i

依次为：1001010A(10*(i-1)+j)

#includevoidmain(){inta[10]={1,2,3,4,5,6,7,8,9,10};intb[6]={2,3,4,5,6,7};intc[10],i,j,k=0,n;for(i=0;

#includeintmain(){inta[20],b[20],i,j=0,max,t;for(i=0;i{scanf("%d",a+i);//输入20个数,如果20个数事先给定,可以不

publicclassTest{publicstaticintfib(intn){if(n==1||n==2)return1;elsereturnfib(n-1)+fib(n-2);}publicst

inta[20];a[0]=1;a[1]=1;for(inti=2;ia[i]=a[i-1]+a[i-2];for(inti=0;i{for(intj=0;j

#include <iostream>using namespace std;int main() {\x09int a[15]

a=round(100*rand(4,4));%生成0-100的随机4*4矩阵a(1,:)%输出第一行...a(:,1)%输出第一列...sum([a(1,:)a(2,1)a(2,4)a(3,1)a(

C语言编写#include#includevoidmain(){intnum[20];//用来存放随机产生的20个数inti,j,sum,max,min,average;//sum,max,min,a

#include#include#defineN20voidmain(){inti,k,j,a[N];k=0;printf("Pleaseinputtwentynozeronumbers\n");fo

i

#include#includeintmian(void){intarr[50]={0};srand((unsignedint)time(NULL));intnIndex=0;for(;nIndex{

#includeintmain(){doubled[10],sum=0,ave=0;inti;for(i=0;i