1.5m*3m贝雷片计算-搜答案-灵鹊做题网

d,符号保留,指数相加.

(m+n)^3-(n+m)(m-n)^2=(m+n)[(m+n)^2-(m-n)^2]=(m+n)[(m+n+m-n)(m+n-m+n)]=(m+n)(2m+2n)=2(m+n)^2

计算 (m+1)(m²+m-1)

解(m+1)(m^2+m-1）=m^3+m^2-m+m^2+m-1=m^3+2m^2-1

解:(2m+1)(2m-1)-m·(3m-2) =(2m)²-1-3m²+2m=4m²-3m²+2m-1=m²+2m-1n²(m-

计算:-2m(m^2-1/2m+3)

-2m(m^2-1/2m+3)=(-2m)*m^2-(-2m)*1/2m+(-2m)*3=-2m^3+m^2-6m

2m+6/m²-4m+4·1/m+3·（m-2)(m+3)/m+3=2（m+3）/（m-2）·1/m+3·（m-2)=2如追加其它问题,采纳本题后点击想我求助,

(2m*7m*3m)/(-42)m=42m/42m=1不懂可追问,有帮助请采纳,谢谢!

n^3/m^3-m^3/n^3-(n/m-m/n)=(n/m-m/n)(n^2/m^2+1+m^2/n^2)-(n/m-m/n)=(n/m-m/n)(n^2/m^2+1+m^2/n^2-1)=(n/m

(3m-1)(m+1)+(2m-1)(m-1)-(3m+5)(m-2)=3m²+2m-1+2m²-3m+1-3m²+m+10=2m²+10=2(m²+

（m-n)^3+(n-m)m^2=（m-n)^3-(m-n)m^2=(m-n)[(m-n)^2-m^2]=(m-n)(m-n+m)(m-n-m)=-n(m-n)(2m-n)=-n(2m^2-3mn+n

原式=(1+2015)m/(2×2)-（2+2014）m/(2×2)=0

={[(－a)²]^m}³×{[(－a)³^m]}＋{[(－a)³]^m]³=[a^(6m)]×[a^(3m)]－[(－a³)^(3m)]=

前面括号和后面括号里是：各有（1+2009）/2=1005项去掉括号,写成1-2+3-4+5-6.+2009-2010相当于1005个-1相加,最后是-1005

(m+3m+5m+...+2009m)-(2m+4m+6m+...+2010m)=2010m/2=1005m

2010m/2=1005m(m+3m+5m+…+2011m)-(2m+4m+6m+…+2010m)=(m+3m+5m+…+2011m)-2m-4m-6m-...-2010m=m-2m+3m-4m+5m

=（m-2m)+(3m-4m)+.(一共2010/2=1005项）+2011m=-1005m+2011m=1006m

原式=(4m²-9)+(2mn-m²+3n²)=3m²+2mn+3n²-9(2mn-m²+3n²)是把(3n-m)(m+n)里面的

(m-1)/(m^2+3m+2)-6/(m^2-m-2)=(m-1)/(m+1)(m+2)-6/(m+1)(m-2)=(m-1)(m-2)/(m+1)(m+2)(m-2)-6(m+2)/(m+1)(m

原式=m^(3*4)+m^(2+10)+m^(1+3+8)=m^12+m^12+m^12=3m^12

m(x+3m)²怎么计算

m(x+3m)²＝m[x2+2·x·3m+(3m)2]=m[x2+6mx+9m2]=mx2+6m2x+9m3

1.5m*3m贝雷片 计算