已知多项式xy³-8x²y-x³y²-y的4次方-6.该多项式是多少次多少项式
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![已知多项式xy³-8x²y-x³y²-y的4次方-6.该多项式是多少次多少项式](/uploads/image/f/4258911-39-1.jpg?t=%E5%B7%B2%E7%9F%A5%E5%A4%9A%E9%A1%B9%E5%BC%8Fxy%C2%B3-8x%C2%B2y-x%C2%B3y%C2%B2-y%E7%9A%844%E6%AC%A1%E6%96%B9-6.%E8%AF%A5%E5%A4%9A%E9%A1%B9%E5%BC%8F%E6%98%AF%E5%A4%9A%E5%B0%91%E6%AC%A1%E5%A4%9A%E5%B0%91%E9%A1%B9%E5%BC%8F)
x^2-2xy+y^2-x+y-1=0(x-y)^2-(x-y)-1=0令a=x-y则a^2-a-1=0a=(1±√5)/2所以x-y=(1-√5)/2,x-y=(1+√5)/2
5x²-3xy-5y²-11xy-8x²+2y²=-3x²-3y²-14xy=-3(x²+y²)-14xy=-3x9+1
=-x-(2y-2+3x)+2(x+4)=-x-2y+2-3x+2x+8=-4x-2y+10
(x+y)²=4x²+2xy+y²=4x²+y²-6=4x²+y²=101/2(x²+y²)-xy=1/2x1
答案15再答:再答:求采纳再答:不用谢!
2x^2-2y^2+3xy-x+8y-6=2x^2+3xy-2y^2+A(2x-y)+B(x+2y)+AB-x+8y-6=A(2x-y)+B(x+2y)+AB=(2A+B)x+(2B-A)y+AB2A
已知x+y=3xy=2那么-x²y-xy²=-xy(x+y)=-2*3=-6如果不懂,祝学习愉快!
x+y分之xy=2,则xy/(x+y)=2xy=2x+2y(-x+3xy-y)分之(3x-5xy+3y)=(3x-5xy+3y)/(-x+3xy-y)=[3x-5(2x+2y)+3y)/[-x+3(2
解2(x+3y-2xy)-(4x+8y-2xy)=2x+6y-4xy-4x-8y+8xy=-2x-2y+4xy=-2(x+y)+4xy=-2×5+4×3=12-10=24x²-3y²
2x²+3xy-2y²-x+8y-6=2x²+3xy-2y²+A(2x-y)+B(x+2y)+AB=2x²+3xy-2y²+(2A+B)x+
-2x^2y(-1/6x^2y^2+3xy^2-xy)+xy=1/3x^4y^3-6x^2y^3+2x^3y^2+xy
x²-3k(1)xy-3y²+k(2)y-4x与多项式-3y²+1/3xy+4y+4x-8的和中不含xy项和y的一次项x²-3k(1)xy-3y²+k
去括号后合并同类项得x^2-(3k-1/3)xy-3y^2-83k-1/3=0k=1/9
x+y=-5,xy=63xy^2+3x^2y=3xy(y+x)=3×6×(-5)=-90
已知多项式3x²y-4xy²+x的三次方-1(1)按y的降幂排列-4xy²+3x²y+x³-1;(2)按y的升幂排列x³-1+3x²
(1)-xy²+2x²y+3x³-4y³=3x³+2x²y-xy²-4y³(2)-xy²+2x²y+
1、项数=2010项,次数=2009次2、第100项:-x^1910y^99;第101项:x^1909y^100,按照y的次数写就可以了3、x=1,y=-1原式=1+1+1+……+1=2010
M=(2x^2y+xy^2)(x-2y)-(2x^2-3xy+xy^2)(-xy)很简单啊.
你的题目好像有误,哪一项里有b阿
(2x+3y-2xy)-(x+4y+xy)-(3xy+2y-2x)=2x+3y-2xy-x-4y-xy-3xy-2y+2x=(2x-x+2x)+(3y-4y-2y)-(2xy+xy+3xy)=3x-3