已知(x-2)∧2 y∧2=3,求y-x

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已知(x-2)∧2 y∧2=3,求y-x
已知x-3y=0,求(2x+y)/(x^2-2xy+y^2)X(x-y)

(2x+y)/(x^2-2xy+y^2)X(x-y)=(2x+y)/(x-y)²*(x-y)=(2x+y)/(x-y)x-3y=0,x=3y(2x+y)/(x-y)=(6y+y)/(3y-y

已知x²+y²+2x-6y+10=0,求x∧y的值

x²+y²+2x-6y+10=0,(x²+2x+1)+(y²-6y+9)=0(x+1)²+(x-3)²=0x=-1y=3

已知2x-y=10 求代数式[(x∧2+y∧2)-(x-y)∧2+2y(x-y)]÷4y的值

[(x∧2+y∧2)-(x-y)∧2+2y(x-y)]÷4y=(2xy+2xy-2y^2)/(4y)=(2x-y)/2=10/2=5

已知x/y=2/3,则2x-y/x+2y的值是多少?

2x-y/x+2y是(2x-y)/(x+2y)吧(2x-y)/(x+2y)=(2x/y-1)/(x/y+2)=(2X2/3-1)/(2/3+2)=1/3÷8/3=1/8

已知:3x=8y.求(1)x+y/y (2)2x+3y/x-2y

3x=8yx/y=8/3(1)x+y/y=x/y+1=8/3+1=11/3(2)2x+3y/x-2y分子分母同时除以y得=(2x/y+3)/(x/y-2)=(16/3+3)/(8/3-2)=(25/3

已知x^2-y^2=27,x-y=3,求y/x的值

(x²-y²)/(x-y)=27/3(x+y)(x-y)/(x-y)=9x+y=9①x-y=3②①+②2x=12x=6①-②2y=6y=3y/x=3/6=1/2

已知X-Y/X+Y=3,求代数式2(x-y)/X+Y-3X+Y/X+Y

X+Y分之X-Y等于3x=-2yX+Y分之2(x-y)减X+Y分之3X+Y=(-x-3y)/(x+y)=1

已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)

因为(x-y)/(x+y)=3,则(x+y)/(x-y)=1/3则5(x-y)(x+y)-(x+y)/2(x-y)=5*3-1/(3*2)=15-1/6=89/6

已知1+2X∧3-3X∧2=3Y 求X=F(Y)

f(x,y)=3x^2y+y^3-3x^2-3y^2+2,下面求驻点坐标:f'x=6xy-6x=0g①f'y=3x^+3y^-6y=09②由①,x=0,或y=1.把x=0代入②y^-2

已知xy=-2,x-y=3,求(x+y)(x-y)-y^2+(x-y)^2-(6x^2y-2xy^2)÷2y

(x+y)(x-y)-y^2+(x-y)^2-(6x^2y-2xy^2)÷2y=(x+y)(x-y)-y^2+(x-y)^2-2y(3x^2-xy)÷2y=(x+y)(x-y)-y^2+(x-y)^2

已知正整数x,y满足2∧x 49=y,求x,y值

x+49=y49=y-x49=(y+x)(y-x)因为x,y是正整数所以y+x>0则y-x=49/(y+x)>0所以y+x>y-x>0而49=7×7=49×1若y+x=7y-x=7解得:x=0y=7x

已知有理数x,y满足1/2│x-2y│=-2│x-4│,求4x∧2-3y

1/2│x-2y│=-2│x-4│化简为|x-2y|=-4|x-4||x-2y|=-|4x-16|所以|x-2y|=0,-|4x-16|=0所以x-2y=0,x=2y4x-16=0,x=4所以y=2所

已知x-2y/2x+3y=3/4,则x:y=

x-2y/2x+3y=3/44(x-2y)=3(2x+3y)4x-8y=6x+9y-2x=17yx/y=-17/2

已知(z-x)∧2-4(x-y)(y-x)=0求x+z-2y+8的值

(z-x)²-4(x-y)(y-z)=0z²-2xz+x²-4xy+4y²+4xz-4yz=0z²+x²+4y²+2xz-4xy-

已知x-2y/3y-x=2/3,则y/x的值是

(x-2y)/(3y-x)=2/33(x-2y)=2(3y-x)3x-6y=6y-2x5x=12y,代入原方程检验通过,故y/x=5/12

已知x-2y=3,则(2x+y-6)/(3x-y-9)=?

x-2y=3则:x=2y+3代入原式,原式=(4y+6+y-6)/(6y+9-y-9)=5y/5y=1

已知y=√2-x-√x-2-3,求y∧x的平方根

则二次根式有意义,得:2-X≥0,X-2≥0,∴X=2,∴Y=-3,Y^X=(-3)^2=9.Y^X的平方根为±3.

已知x+2+|y-3|=0

∵x+2≥0,|y-3|≥0且x+2+|y-3|=0,∴x+2=0,|y-3|=0,∴x+2=0,y-3=0,解得x=-2,y=3,当x=-2,y=3时,x2+y2+3=(-2)2+32+3=16=4

已知x=1/3,y=-1/2,求代数式x-(x+y)+(x+2y)-(x+3y)+(x+4y)-(x+5y)+...-(

原式=x-x+x-x+……-x+(2-1+4-3+5-4+……+2008-2007-2009)y=0+(1×1004-2009)y=-1005y=1005/2