9x² 12x 4=1解方程
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![9x² 12x 4=1解方程](/uploads/image/f/418155-51-5.jpg?t=9x%C2%B2+12x+4%3D1%E8%A7%A3%E6%96%B9%E7%A8%8B)
(2x-16)x4/5=x+16(2x-16)x4=5(x+16)(两边同乘以5)8x-64=5x+80(去括号)3x=80+64=144(移项合并同类项)x=144/3=48所以方程解为x=48
5%x+(300-x)x4%=135x+(300-x)x4=13005x+1200-4x=1300x=1300-1200x=100
(1)x4-12x+323=(x^4+36x^2+324)-(36x^2+12x+1)=(x^2+18)^2-(6x+1)^2=(x^2+6x+19)(x^2-6x+17)(2)x4+7x3+14x2
1,-1,i,-i
2.25x=90x=40
3x-1.2x=91.8x=9x=58.8-4.4x=4.44.4x=4.4x=12.25X4+0.3x=129+0.3x=120.3x=3x=1013x+5X13=16913x+65=16913x=
2.8x4+5x=17.211.2+5x=17.25x=17.2-11.25x=6x=6÷5x=1.2
2x+8.5x2=352x+17=352x=35-172x=18x=912.5x4-3x=23x=50-23x=48x=16
x-7/12*24/35=13/15x-2/5=13/15x=13/15+2/5x=19/15(2/3-1/5)x=14(7/15)x=14x=14÷7/15x=30
23/4x40%+0.4x4.25=5.75x0.4+0.4x4.25=0.4x(5.75+4.25)=0.4x10=42*(x-0.7)=4.8x-0.7=2.4x=3.11/8*(x+0.5)=7
4x+1.5x4=564x+6=564x=50x=25/2
2X+8×4-4X=26∴-2X=26-32解得:X=3
5式相加,3(x1+x2+x3+x4+x5)=1+5-5-3+2=0所以x1+x2+x3+x4+x5=0X1+X2+X3=5,X4+X5+X1=-3,两式相加:X1+(X1+X2+X3+X4+X5)=
X^4+2X^2-1=0(x^2-1)^2=0x^2-1=0x^2=1x=+-1
(x+7)÷1又1/5=6.4(x+7)÷6/5=64/10x+7=64/10*6/5x+7=384/50x=192/25-7x=17/25x-x4/9=4.5÷2又七分之一x-4/9*x=45/10
4x+44=74+x3x=30x=10
这就是最简单的一元一次方程,很容易的步骤如下:先把括号打开:4x+15*4+x=80把常数移到右边:4x+x=80-15*45x=20x=20÷5x=4我现在读的是数学专业(方程方向)的研究生,今年研
1-2x-56=3-x4-2x+4x=3-1+562x=58x=58/2
原式=(X4-2X2+1)+2*(X3-2X2+X)=(X2-1)^2+2*X(X-1)^2=(X-1)^2(X+1)^2+2*X(X-1)^2=(X-1)^2((X+1)^2+2X)=(X-1)^2
(12.5+12.5%)x4=5x5x=50+0.5x=10+0.1x=10.1