5.16求1~100之间所有偶数的和,即2 4 6 8 - 100的流程图怎样写

#include"stdio.h"intmain(){inti,j,n=0;for(i=3;i=i){printf("%4d",i);n++;}}printf("\nzong:%d\n",n);ret

importjava.math.BigDecimal;publicclassTest{publicstaticvoidmain(String[]args){BigDecimalmul=newBigDe

#includemain(){inti,sum=0;for(i=0;i

这个是sql语言写的declare@aintset@a=1while@a

水仙花数是指一个n位数(n≥3),它的每个位上的数字的n次幂之和等于它本身.三位的水仙花数共有4个：153,370,371,407；加一下就可以了,153+370+371+407=1301你可以用程序

#includeintmain(void){inti,sum;sum=0;for(i=1;i

#include"stdio.h"voidmain(){inti=1,m=0;for(i=1;i

只会做第1个:PrivateSubCommand2_Click()Dimi%Fori=100To500x=i\100y=i\10Mod10z=iMod10Ifx+y+z=5ThenPrintiNext

给你自然语言和PASCAL语言各来一段吧.PASCAL的vari,j,sum:longint;beginfori:=1to100doifimod2=1thenbeginwriteln(i);//不想换

PrivateSubCommand1_Click()s=0Fori=100To200IfiMod3=0Thens=s+iEndIfNextiText1.Text=sEndSu

clears=0fori=1to100ifi%30ifi%2=1s=s+iendifendifendfor"1至100之间非3的倍数的所有奇数之和为：",s

#include"stdio.h"voidmain(){ints=0,n,a;for(n=100;n

PrivateSubCommand1_Click()Fori=100To999IfIsPrime(i)Thenn=n+1Printi;IfnMod10=0ThenPrintEndIfNextiEndS

publicclassSumOfEven{\x09publicstaticvoidmain(String[]args){\x09\x09intsum=0;\x09\x09for(inti=1;i

PrivateSubForm_Click()DimaAsIntegerDimbAsIntegerDimcAsIntegerDimSAsIntegerS=2（循环无法找出2因为2是唯一一个能被自己整除的

#include"stdio.h"intgetsum(inta,intb)//要声明a,b为int型{inti;intsum=0;for(a%2==0?i=a:i=a+1;sum=sum+i;i+=2

LOCALlnI,lcZf,lnGw,lnSw,lnBwFORlnI=100to999lcZf=ALLTRIM(STR(m.lnI))lnGw=VAL(SUBSTR(m.lcZf,3,1))lnSw=

#includemain(){longi,j,k;k=10;for(i=1;i再问：--------------------Configuration:Y17-Win32Debug----------

settalkons=100fori=101to210ifi%2!=0s=s+iendifendfo

clearfori=3to100forj=2toi-1ifi%j=0EXITENDIFendfIFj>=iendiendf我运行过了.