因式分解X^2-4Y^2-4 2X^2Y-8Y X^2Y^2
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(x^2+y^2)-4x^2y^2=[(x^2+y^2)+2xy][(x^2+y^2)-2xy]=(x^2+2xy+y^2)(x^2-2xy+y^2)=(x+y)^2*(x-y)^2
x^2-2x-4y^2-4y=(x^2-4y^2)-(2x+4y)=(x+2y)(x-2y)-2(x+2y)=(x+2y)(x-2y-2)
4x^3-4x^2y-(x-y)=4x^2(x-y)-(x-y)=(x-y)(4x^2-1)=(x-y)(2x-1)(2x+1)
4x^3-4x^2y-(x-y)=4x²(x-y)-(x-y)=(x-y)(4x²-1)=(x-y)(2x+1)(2x-1)再问:a^3+1/81(b^3)x(x+4)+4x的绝对
x^2-2y-4y^2+x=(x^2-4y^2)+(x-2y)(第一个括号中用平方差公式)=(x+2y)(x-2y)+(x-2y)(提出公因子x-2y)=(x+2y+1)(x-2y)
利用平方差公式:a²-b²=(a+b)(a-b)4(x+y)²-9(x-y)²=[2(x+y)]²-[3(x-y)]²=[2(x+y)+3(
是(2x-y)²-4x+2y+1原式=(2x-y)²-2(2x-y)+1=(2x-y-1)²
(x+y)(x-y)-4x+x-4y-y-4=(x+y)(x-y)-4(x-y-1)+x-y=(x+y)(x-y)²-4(x-y-1)其实这题的-3x=-4x+x,-5y=-4y-y
原式=(x^2+x)-(4y^2-2y)=(x^2+x+1/4-1/4)-(4y^2-2y+1/4-1/4)=[(x+1/2)^2-1/4]-[(2y-1/2)^2-1/4]=(x+1/2)^2-1/
x^2-y^2-2x-4y-3=(x-1)^2-(y^2+4y+4)=(x-1)^2-(y+2)^2=(x-1+y+2)*(x-1-y-2)=(x+y+1)*(x-y-3)
4(x-y+1)+y(y-2x)=4x-4y+4+y^2-2xy=(y^2-4y+4)-2x(2-y)=(y-2)^2+2x(y-2)=(y-2)(2x+y-2)
x^2(x^2-y^2)-12y^4=x^4-x^2y^2-12y^4=(x^2-4y^2)(x^2+3y^2)您好,很高兴为您解答,skyhunter002为您答疑解惑如果本题有什么不明白可以追问,
4x(y-x)-y²=4xy-4x²-y²=-(4x²-4xy+y²)=-(2x-y)²很高兴为您解答,【the1990】团队为您答题.请点
原式=x^2+4x-(y+3)(y-1)1(y+3)1-(y-1)(y=3)-(y-1)=4故原式=(x+y+3)(x-y+1)小结:遇到两元甚至多元的问题,要善于利用主元法,将其中一个字母当成元,其
3x^4+x^2y-2y^2=(3x²-2y)(x²+y)
原式=(x+2y)(x-2y)-(x+2y)=(x+2y)(x-2y-1)
4(x-y)^2-6(y-x)+2=[2(x-y)-1][2(x-y)-2]=(2x-2y-1)(2x-y-2)很高兴为您解答,skyhunter002为您答疑解惑如果本题有什么不明白可以追问,
x^2y-4y=y(x^2-4)=y(x^2-2^2)=y(x+2)(x-2)如果帮到你,请记得采纳,O(∩_∩)O谢谢
4x^2-16y^2=4(x²-4y²)=4(x+2y)(x-2y)