灵鹊做题网因式分解x3-3x2 4作业帮
来源：学生作业帮助网 编辑：作业帮 时间：2024/04/25 14:03:08
3^2012+6X3^2011-3^2013=3^2011(3+6-3²）=0
原式=x3（y-x）3-x3（y-x）=x3（y-x）（y-x+1）（y-x-1）．
啊,等图片再答：再答：望采纳！
17/6(X24)=3(x-24)17（X+24）=18（X-24）【两边同时乘以6】x=17×24+18×24x=840
3^200-4X3^199+10X3^198=3^198×（3²-4×3+10）=3^198×7∵原式=3^198×7∴3^200-4X3^199+10X3^198能被7整除
设该式为x^3+ax^2+bx+c=x^2(x+a)+b(x+c/b)因为能分解能三个一次式之积,所以有a=c/b,即c=ab该式继续分化,有(x^2+b)(x+a)因为要x^2+b能分解成两个一次式
(1+x+x^2+x^3)^2-x^3设y=1+x+x^2,则(x^3-1)=(x-1)*(1+x+x^2)=(x-1)*y,原式=(y+x^3)^2-x^3=y^2-2*y*x^3+x^6-x^3=
LS你没有写对(X+1)(X^4-X^3+X^2+1)=1+X+X^2+X^5楼主的那个题目如果是:x^5-x^4+x^3+x^2+1没有因式得提拉
(x+y+z)^3-x^3-y^3-z^3=3yx^2+3xy^2+3xz^2+3yz^2+3zx^2+3zy^2+6xyz=3xy(x+y)+3z^2(x+y)+3z(x^2+y^2+2xy)=3x
原式=(x+y)(x-y)+(x-y)(x²+xy+y²)=(x-y)(x²+xy+y²+x+y)原式=a²-ab+2a-6b²-6b=(a
(x+y)³=x³+y³+3x²y+3xy².记忆方法：各立方,然后3x方y,3xy方(x+y)³=x³-y³-3x&#
x5-x4+x3-x2+x-1=x4(x-1)+x2(x-1)+(x-1)=(x-1)(x4+x2+1)=(x-1)(x4+2x2+1-x2)=(x-1)[(x2+1)2-x2]=(x-1)(x2+x
x³-x²-x-1=（x³-x）-（x+1）=x（x²-1）-（x+1）=x（x+1）（x-1）-（x+1）=（x²-x-1）（x+1）
min行末加英文分号其余几行的分号应该用英文分号min=2*x11+x12+3*x13+x14+2*x15+4*x21+2*x22+x23+3*x24+x25+2*x31+x32+x33+3*x34+
x^3+y^3+z^3+(x+y)^3+(y+z)^3+(z+x)^3=[x^3+(y+z)^3]+[y^3+(z+x)^3]+[z^3+(x+y)^3]=(x+y+z)(x^2-xy+y^2-xz+
(x-1)(x^2+ax+2)=x^3+ax^2+2x-x^2-ax-2=x^3+(a-1)x^2+(2-a)x-2=0a-1=-12-a=-1不合理(x-2)(x^2+ax+1)=x^3+ax^2+
(X2-X)X+(X+1)(x+1)(x-1)x+(x+1)(x+1)((x-1)x+1)
x3-y3-x2y+xy2=(x-y)(x2+xy+y2)-xy(x-y)=(x-y)(x2+xy+y2-xy)=(x-y)(x2+y2)
上式=3^198（3^2-4x3+10)=3^198x7,因此能被7整除
x^3+x^2+xy-xy^2=x(x^2+x+y-y^2)=x(x^2-y^2+x+y)=x[(x+y)(x-y)+(x+y)]=x(x+y)(x-y+1)