2x^3-4x^2-1除以一个多项a,商式为2x,余式为x-1-搜答案-灵鹊做题网

题是这样的不,x/4+2x/3+x/2=51去分母得：3x+8x+6x=712x=612/17x=36

x-2除以6-x+2除以3等于1+x-1除以2两边乘6x-2-2(x+2)=6-3(x-1)-x-6=9-3x3x-x=9+62x=15x=7.5

X除以1*2+x除以2*3+x除以3*4+...+x除以2005*2006=X除以1-X除以2+X除以2-X除以3……-X除以2005+X除以2005-X除以2006=X除以1-X除以2006=200

((x+2)/(x^2-2x)-(x-1)/(x^2-4x+4))/((x^2-16)/(x^2+4x))=((x+2)(x-2)-(x-1)x)/((x-2)^2*x)/((x-4)/x)=((x-

=(x/x^2-1)*[(x^2+2x+1)/(x^2+4x+3)]=[x/(x+1)(x-1)]*[(x+1)^2/(x+3)(x+1)]约去相同项得=x/[(x-1)(x+3)]

4x三次除以(-2x)平方-(2x平方-x)除以(1/2x)=4x^3/4x^2-(2x^2-x)/(1/2x)=x-2x(2x-1)/x=x-2(2x-1)=x-4x+2=-3x+2

x^2-x-6分解因式得(x+2)(x-3)x^2-4分解因式得(x-2)(x+2)故(x^2-x-6分之x^2-4+x-3分之x+2)=(x-2)/(x-3)+(x+2)/(x-3)=2x/(x-3

1/(x-1)+1/(x-4)-[1/(x-2)+1/(x-3)]=0通分(2x-5)/(x²-5x+4)-(2x-5)/(x²-5x+6)=0(2x-5)[1/(x²-

(5x-2)/(x-1)+1=(4x+5)/(3x-3)(5x-2+x-1)/x-1=(4x+5)/(x-1)*36x-3=(4x+5)/314x=14x=1

裂项相消.1/(x+a)(x+b)=【1/(x+a)-1/(x+b)】*1/(b-a)一般都是这种形式.特别是你那道题的形式应该让你联想起来这种形式.比如1/(x+1)(x+3)+1/(x+3)(x+

x/2>x/33x>2x3x-2x>0x>0

ax^3+bx^2+cx+d-(5x+4)=ax^3+bx^2+(c-5)x+(d-4)整除(x^2-x+2)(x^2-x+2)(ax+e)=ax^3-ax^2+2ax+ex^2-ex+2e=ax^3

设多项式为ax^3+bx^2+cx+d显然ax^3+bx^2+cx+d=(x^2-x+2)[ax+(a+b)]+(c-a+b)x+d-a-b由于余式等于5x+4所以c-a+b=5,d-a-b=4ax^

有什么问题的亲欢迎向我或者我的团队【定向求助】哦我们将在第一时间内尽力为您解答

4x÷x-2-1=3÷2-x4-2-1=1.5-x1=1.5-xx=-0.5

去分母：2(x+1)=3(x-1)2x+2=3x-32x-3x=-2-3-x=-5x=5经检验此为原方程的根

[x(3-4X)+2X方(X-1)]除以（-2X）=(3x-4x²+2x³-2x²)÷﹙-2x)=(2x³-6x²+3x)÷﹙-2x)=-x²

1/(5-x)+2/(4-x)+3/(3-x)=-31/(5-x)+2/(4-x)=3/(x-3)-3[(4-x)+2(5-x)]/[(5-x)(4-x)]=[3-3(x-3)]/(x-3)(14-3

解[(4x²-x³-2x)÷2x]-(x-1)²=(2x-1/2x²-1)-(x²-2x+1)=2x-1/2x²-1-x²+2x-

x=10