函数递归调用求斐波拉契数列第30项及前30项的和

#includelongintfn(int);voidmain(){printf("%d",fn(10));}longintfn(intm){longinttemp;if((1==m)|(2==m))

#include#includemain(void){intn,i;printf("请输入n的值\n");scanf("%d",&n);intsum1=1,sum2=2,sum;for(i=3;i

#include#defineN20main(){intf(intn);inti;for(i=1;i

elsef=s(t)+(480*m+15*n+20*s(t))*(k-s(t))/k+(k-s(t)-(480*m+15*n+20*s(t))*(k-s(t))/k)*(1-(k-s(t)-(480*

就是自己需要调用自己,f（x）=x-f（x-1）,如果x=5,那么带入的时候就在一直调用f（x）

#includeusingnamespacestd;intmain(){intn,a=1,b=2;cout再问：^那这个是什么符号，这个没学过，有用temp做的么？再答：是位运算的异或符号；也可以用t

functionfibonacci(n:integer):integerbeginif(n=0)thenResult:=0;if(n=1)thenResult:=1;if(n>1)thenResult

/>#includeusingnamespacestd;longunsignedfun(intn){if(n>1)returnn*fun(n-1);return1;}voidmain(){intn;c

#include"stdio.h"intmain(){inta,b,c,i;a=1;b=1;printf("%d%d",a,b);for(i=3;i

intFibona(intn){intm;if(n==1)return(1);elseif(n==2)return(1);else{m=Fibona(n-1)+Fibona(n-2);return(m

#include<stdio.h>int calc(int n){\x09int i,sum;\x09i=1,sum=0;\x09while(i<=n)

#includeintfact(int);main(){inti,sum=0;for(i=1;i

#includelongfib(intn){inta;if(n==1)a=1;elseif(n==2)a=1;elsea=fib(n-1)+fib(n-2);returna;}voidmain(){\

functiongqj=erfen(p,a,b,e)ifabs(b-a)

#includemain(){intn,i,j,k;while(scanf("%d",&n)==1){if(n==1||n==2){printf("%d\n",1);cont

#includeintfibo(intn){if(nreturn1;elsereturnfibo(n-1)+fibo(n-2);}intmain(){intn;scanf("%d",&n);print

#includeusingnamespacestd;longunsignedfun(intn){if(n>1)returnn*fun(n-1);return1;}voidmain(){intn;cou

publicclassFibonacci1{publicstaticlongfib(intn){longf1=1,f2=1;longm=0;if(n

递归函数如下：首先斐波拉楔数列的前n项和递推公式为S（n）=S（n-1）+S（n-2）+1；(根据通项公式a[n]=a[n-1]+a[n-2]很容易推导出来)递归函数如下所示;intsum_Fibon

#includefib(intn){if(n==0)return(0);elseif(n==1)return(1);elsereturn(fib(n-1)+fib(n-2));}main(){intn