先化简再求值(x-x加1分之x)除以x的2次加2x加1分之-搜答案-灵鹊做题网

题目有误吧(x-x)x-1分之4(x-x)+(x-2)再问：(x方-x)(x-2)方再答：

[(x-4)/(x^2-1)]÷[(x^2-3x-4)/(x^2+2x+1)]+1/(x-1)=[(x-4)/(x+1)(x-1)]÷[(x-4)(x+1)/(x+1)^2]+1/(x-1)=[(x-

原式=【x(x+1)-x】/(x+1)÷【x²-1+1】/(x²-1)=x²/(x+1)÷x²/(x+1)(x-1)=x-1代入x=1原式=1-1=0如果本题有

=(x²-x-x)/(x+1)÷(x²-1+1)/(x+1)(x-1)=x(x-2)/(x+1)×(x+1)(x-1)/x²=(x-2)(x+1)/x取x=2则原式=0

（x加1分之x减1加x平方减1分之2x）除以x平方减1分之1=【（x-1）²/（x+1）*（x-1）+2x/（x+1）*（x-1）】*（x+1）*（x-1）=【（x²+1）/（x+

原式=(x+1)/x÷(2x²-1-x²)/2x=(x+1)/x÷(x²-1)/2x=(x+1)/x÷(x+1)(x-1)/2x=(x+1)/x*2x/(x+1)(x-1

原式=[(x-1)/(x+1)+2x/(x^2-1)]/[1/(x^2-1)]通分=[(x-1)^2+2x]/(x^2-1)*(x^2-1)=(x-1)^2+2x=x^2-2x+1+2x=x^2+1再

(x-1/x)/((x²-2x+1)/x)=((x²-1)/x)/((x-1)²/x)=(x+1)(x-1)/(x-1)²=(x+1)/(x-1)=6/4=3/

【先化简再求值】（x-1）分之x÷【(1-x分之1）-1-x】=（x-1）分之x÷（x^2/(1-x)）=-1/xx=1时,原式无意义,x=2时,原式=-1/2,x=0时,原式无意义【选择题】下列约分

(x²+x-2)分之(1+x)÷[x-2+(x+2)分之3]=(x²+x-2)分之(1+x)÷[(x+2)分之(x²-1)]=[(x+2)(x-1)]分之(1+x)×(x

原式=[3x/(x-1)-x/(x+1)]×[(x²-1)/x]={3x(x+1)/[(x-1)(x+1)]-x(x-1)/[(x-1)(x+1)]}×[(x-1)(x+1)/x]=[3x(

=(x+1)(x-1)/x÷(x-2x+1)/x=(x+1)(x-1)/x×[-x/(x-1)==x+1当x=√2时原式=√2+1再问：对不起，是我没说明白x²-1÷(1-x分之2x-1)是

答案是不是二分之X+2的平方—X的平方之一最后是5+2倍的根下2

/>（2x-x分之1+x的平方）除以x分之x-1,其中x=根号2=[2x²-(1+x²)]/x÷(x-1)/x=(x²-1)/(x-1)=(x-1)(x+1)/(x-1)

1/(x-3)+6/(9-x^2)=1/(x-3)+6/(3-x)(3+x)=(x+3-6)/(x-3)(x+3)=1/(x+3)=1/(-2)=-1/2