任意一个整数插入已排序的整型数组
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/16 03:44:31
#includeintmain(){intkey,index;intarr[10]={1,2,3,4,5,6,7,8,9,10};printf("输入整数Key:\n");scanf("%d",&ke
#include#defineSIZE20voidmain(){printf("请输入10个整数:\n");inta[SIZE];intn=10,i,j,k,b;for(i=0;i
#include#includeintmain(){inta[20]={3,6,9,23,34,56,78};inti,n;intflag=0;printf("Input:");scanf("%d",
假设是增序的算法如下,时间复杂度为O(n):#includeboolfindTwoNumber(intarray[],intlen,intx){intlow=0;inthigh=len-1;while
代码如下:#include <stdio.h>#define N 11int main(int argc,char *argv[
#includevoidarr(int*a,intn);/*定义排序函数*/voidinsert(int*a,intnum);/*插入并排序函数*/intn=10;/*定义数据个数,可修改*/void
#includeintmain(){inta[7]={12,23,34,45,56,67};//初始化,使a中的元素值非递减有序inti,j,x;printf("Pleaseinputxbeinser
#include//数列由小到大排列voidinsert(inta[],intm){\x09intb[11],i,j;\x09for(i=0,j=0;i
voidmain(){\x05inta,b,temp,m;\x05\x05scanf("%d%d",&a,&b);if(a
#includeintmain(void){\x05inti,num,t=0,z;\x05inta[10]={1,2,8,17,23,24,59,62,101};//一开始有9个加上新的1个需要的是1
publicstaticvoidmain(String[]args){int[]nums={99,88,77,66,55,44,33,22,11,0};int[]nums_new=newin
#include<stdio.h>intmain(){ inta[20]={1,7,8,17,23,24,59,62,101}; inti,j,x; x=50
for(i=0;i
voidInsert(inta[N],n){for(inti=0;i
inti,j,a[20],t,number,k;\x09\x09for(i=0;i
ifxmod2=0thenmsgbox"是偶数"elsemsgbox"是奇数"
main(){inta[10]={0,-1,12,96,188,249,800};intx,i,j=6;printf("输入一个数:");scanf("%d',&x);a[0]=x;i=j;while
代码敲一下.#include<iostream>usingnamespacestd;classStudent{private:intid;floatscore;public:Student
排序趟数太模糊啦比较次数有关插入次数无关其实程序更在意复杂度