以3为底4的对数乘以4为底8的对数乘以以8为底m为对数等于以4为底16的对数-搜答案-灵鹊做题网

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(ln(1/3)/ln5)(ln6/ln3)(lnx/ln6)=2得x=1/25再问：能提供解析吗?再答：就是换底约掉就剩-(lnx/ln5)=2在换回来就是负的五为底x的对数为2解得x=1/25

D首先化减:log8(M)*log3(4)=log4(16)=2log8(M)=2/log3(4)=log3(9)/log3(4)运用换底公式log3(9)/log3(4)=log4(9)所以log8

[log2(9)]*[log3(2)]=[log2(3²)]*[1/log2(3)]=2[log2(3)*[1/log2(3)]=2

㏒2（16）=㏒2（2的4次方）=4同理,㏒3（9）=㏒3（3的2次方）=2所以,原式=4×2=8

log以2为底25的对数乘以以3为底4的对数乘以5为底9的对数=lg25/lg2*lg4/lg3*lg9/lg5=2lg5/lg2*2lg2/lg3*2lg3/lg5=4lg5/lg3*2lg3/lg

4

log(3)4*log(4)8*log(8)m=log(4)2同底转换.(lg4/lg3)*(lg8/lg4)*(lgm/lg8)=1/2lgm/lg3=1/2lgm=lg√3m=√3有不懂的地方请追

是64log以2为底3的对数乘以log以81为底64的对数=lg3/lg2*(lg64/lg81)=lg3/lg2*(6/4lg2/lg3)=3/2

为了书写方便,不妨记以a为底b的对数为：log【a】b(log【2】5+log【4】125)×[(log【3】2)/(log【√3】5)]=[(lg5)/(lg2)+(lg125)/(lg4)]×{[

log以4为底(x+12)的对数乘以log以x为底2的对数=【ln（x+12）/ln4】×【ln2/lnx】=ln（x+12）/lnx=ln（x+12-x）其中x+12-x＞0,即-3＜x＜4

9乘以log以3为底5的对数=9×[(log5)÷(log3)]=9×[0.69897000433601880478626110527551÷0.477121254719662437295027903

log2(25)*log3(4)*log5(9)=lg25/lg2*lg4/lg3*lg9/lg5(换底公式)=lg5^2/lg2*lg2^2/lg3*lg3^2/lg5=2lg5/lg2*2lg2/

log8^9*log3^2=2log8^3*log3^2=2/3log2^3*log2^3=2/3*lg3/lg2*lg2/lg3=2/3

楼上写错了[log(3,2)+log(9,2)]*[log(4,3)+log(8.3)]=[log(3,2)+1/2log(3,2)]*[1/2log(2,3)+1/3log(2,3)]=3/2log

请看图

log8(9)*log9(8)=(log9/log8)*(log8/log9)=1

首先必须满足3^x-1>0原式为：(lg(3^x-1)/lg4)*(lg(3^x-1)-lg16)/lg0.25=0△=4(lg4)^2-3(lg4)^2恒大于零解为lg(3^x-1)>=1.5lg4

log89×log2732=lg9/lg8×lg32/lg27=(2lg3)/(3lg2)×5lg2/(3lg3)=2/3×lg3/lg2×5/3×lg2/lg3=10/9希望对您有所帮助如有问题,可

(以2为底3的对数+以4为底9的对数+以8为底27的对数+以16为底81的对数+以32为底243的对数）-5倍的以2为底二分之三的对数=lg3/gl2+2lg3/(2lg2)+3lg3/(3lg2)+