从键盘中输入一串字符,以#结束,统计其中有多少个单词

voidStrOL(void){intn;charline[80];/*字义一个长度为80的字符型数组*/inti;for(i=0;i{line[0]=0;n=strlen(xx[i]);/*strl

#includeintmain(){chara,b;a=getchar();scanf("%c",&b);printf("a=%c\n",a);printf("b=%c\n",b);return0;}

#include#includevoidmain(){intw=0,k=0,n=0,z=0;//w为字母个数,k为空格个数,n为数字个数,z为其他字符个数charch;scanf("%c",&ch);

你所写的代码是正确的,想要查看,请用这个：#includeintmain(){charch;scanf("%c",&ch);if(ch>='A'&&ch

1.a2、n++

除Z以外的都加1,Z的话-25,@的话退出,一个循环,取每一个字符,判断后运算就行了.

inti;floatf;doubled;charc;scanf("%d,%f,%f,%c",&i,&f,&d,&c);printf("%d,%f,%f,%c\n",i,f,d,c);doublesum

记住一个定理：三角形两边之和大于第三边,两边之差小于第三边.这就足够了!

#include#defineN100intmain(){inta[N],i,j,count1,count2;floatave1,ave2;count1=count2=ave1=ave2=0;for(

PrivateSubForm_Click()DimsAsInteger,maxAsInteger,minAsInteger,nAsInteger,averageAsSingle,sumAsLongDo

#include <stdio.h>int main(void){    int count=0; &nbs

1、clears=0m=1fori=1to10input"请输入一个数："toaifa/2=int(a/2)s=s+aelsem=m*aendifendfor?"奇数的积是：",m?"偶数的和是：",

intmain(){charstr1[50],str2[50];printf("请输入字符串:|n");gets(str1);for(inti=0;str1[1]='\0';i++){if(str1[

#includevoidmain(){intn=0;floatx,sum=0,aver=0;scanf("%f",&x);n++;while(x!=-1){sum+=x;n++;scanf("%f",

#includeintmain(){charc[256];inti=0;while((c[i++]=getchar())!='\n');c[i]='\0';i=0;printf("%s",

#includevoidmain(){intmax(intx,inty;inta,b,c;scanf("%d,%d",&a,&b);c=max(a,b);printf("Thelargestnumbe

　　如图望采纳!

程序很简单,仔细看吧：vara:array['0'..'9']oflongint;b:array['0'..'9']ofchar;c,i,j,tt:char;t:longint;begin//初始化f

#includeusingnamespacestd;intmain(){inta[1000],b,sum,min;min=0;//可以是你输入数字的最小值sum=0;for(inti=0;;i++){

programdaihuan;vars,e,tmp:string;i,j,k,l:integer;t:char;procedureswap(t:char);begincasetof'a':tm