(x-30)(100-2x)=200怎么解

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(x-30)(100-2x)=200怎么解
1X+2X+3X…+98X+99X+100X=50500X X等于多少?

1X+2X+3X…+98X+99X+100X=5050x=50500x=10

已知x^4+x^3+x^3+x^2+x^1+1=0,求x^100+x^99+x^98+x^97+x^96的值

x^4+x^3+x^2+x+1=0,x^100+x^99+x^98+x^97+x^96=x^96(x^4+x^3+x^2+x+1)=x^96*0=0

已知x^4+x^3+x^2+x^2+1=0,求x^100+x^99+x^98+x^97+x^96的值

因为x^4+x^3+x^2+x^2+1=0所以x^100+x^99+x^98+x^97+x^96=x^96(x^4+x^3+x^2+x^2+1)=x^96*0=0

x^4+X^3+X^2+X^1+1=0求x^100+X^99+X^98+X^97+X^96的值

x^100+X^99+X^98+X^97+X^96=x^96(x^4+X^3+X^2+X^1+1)=k^96*0=0

x^5+x^4 = (x^3-x)(x^2+x+1)+x^2+x

是这样的:x^5+x^4=x^3(x^2+x)=(x^2+x)[(x^3-1)+1]=(x^2+x)(x^3-1)+x^2+x=[x(x+1)(x-1)](x^2+x+1)+x^2+x=(x^3-x)

1/x(x+1)(x+2)+1/(x+1)(x+2)(x+3).+1/(x+98)(x+99)(x+100)=?

1/x(x+1)(x+2)+1/(x+1)(x+2)(x+3).+1/(x+98)(x+99)(x+100)=(1/2){[1/x(x+1)-1/(x+1)(x+2)]+[1/(x+1)(x+2)-1

已知x=100,求x(x+1)分之1+(x+1)(x+2)分之1+(x+2)(x+3)分之1+.+(x+99)(x+10

1/X(X+1)+1/(x+1)(x+2)+.+1/(x+99)(x+100)=1/x-1/(x+1)+1/(x+1)-1/(x+2)+.+1/(x+99)-1/(x+100)=1/x-1/(x+10

先化简再求值(x+3x+5x+7x+.+101x)-(2x+4x+6x+...100x),其中x=51分之2

=x+(3x-2x)+(5x-4x)+……+(101x-100x)=x+x+……+x=51x=51×2/51=2

2x+3x+4x+5x+x+6x+7x=100

2x+3x+4x+5x+x+6x+7x=10028x=100x=100/28x=25/7

30%X-30%X-[(X-30%X)×20%-2]-30%X=28怎么解

30%X-30%X-[(X-30%X)×20%-2]-30%X=280-(0.7X×0.2-2)-0.3X=28-0.14X+2-0.3X=280.44X=-26X=-59又11分之1

x-2x+3x-4x+...+99x-100x=25

x-2x+3x-4x+...+99x-100x=25(1-2)x+(3-4)x+…+(99-100)x=25-x-x-…-x=25-50x=25x=-1/2

(X+X)+(X-X)+(X*X)+(X/X)=100

(X+X)+(X-X)+(X*X)+(X/X)=1002X+0+X*X+1=1002X+X*X=99X(X+2)=99X=9再问:请问X(X+2)=99解为什么就等于9了呢没看懂再答:换成算术法你就明

X+X+X+X+X+X+100X=1690 问:X等于多少

X+X+X+X+X+X+100X=1690106x=1690x=845/53

解方程:2x+4x+6x...+100x=1-(x+3x+5x+...+99x)

2x+4x+6x...+100x=1-(x+3x+5x+...+99x)x(2+4+6+...+100)=1-x(1+3+5+...99)x(2+4+6+...+100)+x(1+3+5+...+99

x/2+x/6+x/12+x/20+x/30+x/42=1

x/2+x/6+x/12+x/20+x/30+x/42=136x/42=1x=7/6

30X-2X=84 5.8X-X=60 6.6X-5X=8 4X-X=24 1.5X-X=1

28X=84X=30.8X=60X=751.6X=8X=53X=24X=80.5X=1X=2再问:要过程啊我这是作业汗快点把我很急谢谢你啊再答:30X-2X=8428X=8428X÷28=84÷28X

计算:(x+1)x=7 (x-1)(x+2)=30 (3-x)(3-x)+x=9

X^2+X-7=0X1=根29-1X2=-1-根29X^2+X-2=0X1=-2X2=19-6X+X^2+X=9X^2-5X=0X(X-5)=0X1=0X2=5

解一元一次方程 x/2+x/6+x/12+x/20+x/30+x/42=6

原方程化为:(1/2+1/6+1/12+1/20+1/30+1/42)x=6【(1-1/2)+(1/2-1/3)+(1/3-1/4)+(1/4-1/5)+(1/5-1/6)+(1/6-1/7)】x=6

x^2=(x+30)X(x-18)怎么解

问题是不是X2=(X+30)*(X-18)啊?要是上面的话就这样X2=X*X-X*18+30*X-30*18=X2+12X-540移项得:X2-X2-12X=-540,即-12X=-540,X=45*