(9x³-6x² 3x)÷(-3x)-搜答案-灵鹊做题网

原式=(x-3)^2)*[(x+3)/(x-3)(x-6)]=(x+3)(x-3)/(x-6)=(x^2-9)/(x-6)

(x+1-1/1-x)÷(x-x²/x-1)=[(x+1)+1/(x-1)]×[-(x-1)/x(x-1)]=(x²-1+1)/(x-1)×(-1/x)=-x/(x-1)(x-4/

A={x|x^2-2x-3<3(1-x)}={x|x^2+x-6<0}={x|-3<x<2}B={x|9-x^2>6-2x}={x|x^2-2x-3<0}={x|-

|x-1|+|x-10|表示数轴上x到1的距离+x到10的距离.显然最小值是9,此时x只要在1到10之间就好.类似的,|x-2|+|x-9|的最小值是7,此时x在2到9之间就好.|x-3|+|x-8|

x(1+2+...+9)=x(9-8-7-...-1)x=0记得采纳啊

X²-6x+9 x²-9 x+3

(x^2-6x+9)÷x^2-9x+18/x+3=(x-3)^2÷(x+3)(x-3)+18/(x+3)=(x-3)/(x+3)+18/(x+3)=(x+15)/(x+3)

x²+2x／x²-6x+9÷x²-4／x²-3x=x(x+2)/(x-3)^2*x（x-3）/（x+2)(x-2)=x^2/[(x-3)(x-2)]

中间错了原式=(x+2)/(x-3)(x+2)+2x/x(x-3)-(x+1)/(x-3)²=1/(x-3)+2/(x-3)-(x+1)/(x-3)²=3/(x-3)-(x+1)/

(2x-6)/(x²-4x+4)÷(3-x)/(x²+6x+9)×(2-x)/(x+3)=2（x-3)/(x-2)^2X(x+3)^2/(3-x)X(2-x)/(x+3)=2（x-

（x²-6x+9）÷x+3分之x²-9x+18,=（x²-6x+9）×（x+3)/（x²-9x+18）=（x-3)²(x+3)/[(x-3)(x-6)

原式=(x-3)/(x²+x)*1/(x-3)²约去x-3=1/[(x-3)(x²+x)]=1/(x³-2x²-3x)

原式=(x+2)/(x+2)(x-3)-2x/x(x-3)-(x+1)/(x-3)²=1/(x-3)-2/(x-3)-(x+1)/(x-3)²=-1/(x-3)-(x+1)/(x-

1.(x^3-3x^2)/(x^2+5x+6)÷(x^3-9x)/(x^2+2x-3)*(x+2)/(2x)=x^2(x-3)/(x+2)(x+3)*(x+3)(x-1)/x(x+3)(x-3)*(x

解1：原式=x(x-1)/(x+1)*(x+1)/x=x-1解2：原式=(x+3)^2/(x+3)(x-3)*(x-3)/(x+2)=(x+3)/(x-3)*(x-3)/(x+2)=(x+3)/(x+

(x+2)/(x^2-x-6)+2x/(x^2-3x)-x/(x^2-6x+9)=(x+2)/[(x-3)(x+2)]+2x/[x(x-3)]-x/[(x-3)^2]=1/(x-3)+2/(x-3)-

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x^9+x^6+x^3-14

设x^3=a,则题目可变为下式:a^3+a^2+a-14=a^3-8+a^2+a-6=(a-2)(a^2+2a+4)+(a-2)(a+3)=(a-2)(a^2+2a+4+a+3)=(a-2)(a^2+

题目都写不清楚.x=0

分式计算：[(x²+2x)／(x²-6x+9)]÷[(x²-4)／(x²-3x)]原式=[x(x+2)/(x-3)²]•[x(x-3)/(